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MAVERICK [17]
3 years ago
14

How many significant digits are in the number 2370.0?

Chemistry
2 answers:
xz_007 [3.2K]3 years ago
4 0

Answer:

2370.0 contains 4 significant digits and Option (c) is correct .

1.20\times 10^{-3}\ contains\ three\ significant\ digit.

Option (b) is correct .

Step-by-step explanation:

Rules for finding significant digit .

1 : Non-zero digits are always significant.

2: Any zeros between two significant digits are significant .

3: Trailing zeros in the decimal number is also significant.

As the number given be 2,370.0.  

= \frac{23700}{10}

Simplify the above

= 2370

Thus by using the rule given above.

2370.0 contains 4 significant digits.

Option (c) is correct .

As the number given be 0.00120 .  

= \frac{120}{100000}

Simplify the above

= \frac{1.20}{1000}

= 1.20\times 10^{-3}

Thus by using the rule given above.

1.20\times 10^{-3}\ contains\ three\ significant\ digit.

Option (b) is correct .

den301095 [7]3 years ago
3 0

2370.0 has five significant digits.

Hope this helps!

Davinia.

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san4es73 [151]

Answer : The moles of H_2SO_4 are, 2.125 mole.

Explanation : Given,

Molarity of H_2SO_4 = 8.500 M

Volume of solution = 250 mL  = 0.250 L    (1 L = 1000 mL)

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Moles of }H_2SO_4}{\text{Volume of solution (in L)}}

Now put all the given values in this formula, we get:

8.500M=\frac{\text{Moles of }H_2SO_4}{0.250L}

\text{Moles of }H_2SO_4=2.125mol

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5 0
3 years ago
A particular atom contains 29 electrons, 34 neutrons, and 29 protons. what is the identity of this element and what is its atomi
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Answer:

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             Atomic Number =  29

Explanation:

Given Data:

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Number of Protons  =  29

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Atomic Number is defined as the number of protons present in the nucleus of an element. As the given number of protons are 29, therefore, the atomic number of this element is also 29.

Secondly, if the element is in neutral state then its number of protons must be equal to the number of electrons present in it. So, in neutral state this element will contain 29 electrons. Therefore, the electronic configuration is as follow,

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Now using electronic configuration one can easily identify the position of this element in periodic table. As the valence shell is 4, so it belongs to period 4 and there are 9 electrons in d-subshell so it belongs to transition elemnts and transition element with 9 electrons in d shell is Copper. Also, the stable electronic configuration of copper is written as,

                                     1s², 2s², 2p⁶, 3s², 3p⁶, 4s¹, 3d¹⁰

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Answer:

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