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Karo-lina-s [1.5K]
3 years ago
6

Describe the thin flat layering found in most metamorphic rocks.

Chemistry
1 answer:
Solnce55 [7]3 years ago
5 0
The thin flat layering found in most metamorphic rocks is called the FOLIATION....(sorry,thats all i know)
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How many hydrogen atoms are in 4.40 mol of ammonium sulfide
katrin2010 [14]
 The number  of hydrogen  atoms  that are  in 4.40  mol  of ammonium sulfide is  2.12 x10^25  atoms

      calculation
 find the number of moles  of Hydrogen  in ammonium sulfide  (NH4)2S

that is  4.40  x  number of hydrogen atoms in (NH4)2S ( 4x2= 8  atoms)

moles is  therefore=  4.40  x8= 35.2  moles

by  use of  Avogadro's law  constant

that is  1mole =  6.02 x10^23 atoms
         35.2  moles=?

by  cross multiplication
  {35.2 moles x 6.02 x10^23} /1 mole  = 2.12  x10^25  atoms
5 0
3 years ago
Read 2 more answers
When FeC13 is ignited in an atmosphere of pure oxygen, this reaction takes place. 4FeCl3(sJ 30lgJ ~ 2F~0 (sJ 6Cl2(gJ If 3.00 mol
oksano4ka [1.4K]

Answer : The reagent present in excess and remains unreacted is, O_2

Solution : Given,

Moles of FeCl_3 = 3.00 mole

Moles of O_2 = 2.00 mole

Excess reagent : It is defined as the reactants not completely used up in the reaction.

Limiting reagent : It is defined as the reactants completely used up in the reaction.

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

2FeCl_3(s)+O_2(g)\rightarrow 2FeO(s)+3Cl_2(g)

From the balanced reaction we conclude that

As, 2 moles of FeCl_3 react with 1 mole of O_2

So, 3.00 moles of FeCl_3 react with \frac{3.00}{2}=1.5 moles of O_2

From this we conclude that, O_2 is an excess reagent because the given moles are greater than the required moles and FeCl_3 is a limiting reagent and it limits the formation of product.

Hence, the reagent present in excess and remains unreacted is, O_2

4 0
3 years ago
A pure white crystalline compound was found to melt at 112.5-113.0oC when taken on a melting point apparatus, and on further hea
Sergeeva-Olga [200]

According to the question, the determined melting point of the compound is 112.5-113.0oC. When the solidified compound was retried, the melting point was found to be 133.6-154.5oC. This greater range higher than  112°C is caused by reusing samples leads to errors.

A pure sample is known by its sharp melting point. A pure sample does not melt over a large range. We can see this in the predetermined melting points of the pure sample(112.5-113.0oC).

However, reusing a sample introduces errors because the pure sample may become contaminated leading to a larger and higher range of melting point (133.6-154.5oC) which is far above  112°C.

Learn more: brainly.com/question/5325004

8 0
3 years ago
Which element am I? Give my symbol ONLY! What a robber says as he's running away! ​
Olin [163]

Answer:

ummmmmmmmmmmmmmmm..mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

Explanation:

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5 0
3 years ago
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Which segement of the heating curve shown above represents an increase in the potential energy, but no change in the kinetic ene
Ede4ka [16]

Answer: Option (b) is the correct answer.

Explanation:

Kinetic energy is defined as the energy obtained by the molecules of an object due to their motion.

Also, it is known that kinetic energy is directly proportional to temperature.

Mathematically,       K.E = \frac{3}{2}kT

where,             T = temperature

Whereas potential energy is defined as the energy obtained by an object due to its position.

Mathematically,      P.E = mgh

where,             m = mass

                        g = acceleration due to gravity

                        h = height

Therefore, in the given curve when temperature remains constant then kinetic energy of molecules will also remain.

Hence, we can conclude that the segment QR represents an increase in the potential energy, but no change in the kinetic energy.

7 0
3 years ago
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