Data:
p = 1 atm
V = 10 m * 8 m * 5 m = 400 m^3 = 400,000 liter
To = 0 + 273.15K = 273.15K
Tf = 20 + 273.15K = 293.15K
No - Nf =?
2) Formula
pV = NRT => N = pV / (RT)
3) solution
No = pV / (RTo)
Nf = pV / (RTf)
=> No - Nf = [pv / R] [ 1 / To - 1 / Tf ]
=> No - Nf = [1atm*400,000liter / 0.0821 atm*liter/K*mol ] [ 1 / 273.15 - 1 / 293.15]
No - Nf = 1216.9 moles ≈ 1217 moles
Answer: 1217 moles
Answer:
you just think it and you would make it.
Explanation:
its gonna be easy if you just think what would you do for it.☺
The balanced equation for the above reaction is as follows;
C + H₂O ---> H₂ + CO
stoichiometry of C to H₂O is 1:1
1 mol of C reacts with 1 mol of H₂O
we need to find which is the limiting reactant
2 mol of C and 3.1 mol of H₂O
therefore C is the limiting reactant and H₂O is in excess.
stoichiometry of C to H₂ is 1:1
then number of H₂ moles formed are equal to C moles reacted
number of H₂ moles formed = 2 mol