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3 years ago

A dentist uses a concave mirror to examine a tooth that is 1.00

Physics

1 answer:

Zanzabum3 years ago

3 0

Answer:

-2.2cm

Explanation:

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Based on the image below what would an observer on the nighttime side of earth observe?

sertanlavr [38]

I would love to help; where’s the picture?

3 0

3 years ago

A series RL circuit includes a 6.05 V 6.05 V battery, a resistance of R = 0.655 Ω , R=0.655 Ω, and an inductance of L = 2.55 H.

Ivenika [448]

Answer:

The induced emf 1.43 s after the circuit is closed is 4.19 V

Explanation:

The current equation in LR circuit is :

$I=\frac{V}{R} (1-e^{\frac{-Rt}{L} })$ .....(1)

Here I is current, V is source voltage, R is resistance, L is inductance and t is time.

The induced emf is determine by the equation :

$V_{e}=L\frac{dI}{dt}$

Differentiating equation (1) with respect to time and put in above equation.

$V_{e}= L\times\frac{V}{R}\times\frac{R}{L}e^{\frac{-Rt}{L} }$

$V_{e}=Ve^{\frac{-Rt}{L} }$

Substitute 6.05 volts for V, 0.655 Ω for R, 2.55 H for L and 1.43 s for t in the above equation.

$V_{e}=6.05e^{\frac{-0.655\times1.43}{2.55} }$

$V_{e}=4.19\ V$

5 0

3 years ago

You hear three beats per second when two sounds tones are generated. The frequency of one tone is known to be 610 Hz. The freque

tiny-mole [99]

The frequency of the other wave is 613 Hz or 607 Hz.

The difference between the frequencies of two waves is called the beat frequency.

Here, one wave has a frequency 610 Hz and the beat frequency is 3 beats per second.

Which has a higher frequency is not mentioned. Therefore, there are two possibilities.

Δf = | 610 - 613 | = 3

Δf = | 610 - 607 | = 3

Therefore, the frequency of the other wave is 613 Hz or 607 Hz.

Learn more about beat frequency here:

brainly.com/question/14157895

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7 0

2 years ago

A package of aluminum foil contains 50. ft2 of foil, which weighs approximately 7.5 oz . Aluminum has a density of 2.70 g/cm3. W

Tems11 [23]

Answer:

The thickness of the foil is 0.017 mm.

Explanation:

Given that,

Weight = 7.5 oz = 212.6175 gm

Density = 2.70 g/cm³

Area of aluminium = 50 ft² = 46451.52 cm²

We need to calculate the thickness of the foil

Using formula of density

$\rho=\dfrac{m}{V}$

$\rho=\dfrac{m}{A\times t}$

$t=\dfrac{m}{A\times \rho}$

Where, A = area

t = thickness

m = mass

Put the value into the formula

$t=\dfrac{212.6175}{46451.52\times2.70}$

$t=0.00170\ cm$

$t=0.017\ mm$

Hence, The thickness of the foil is 0.017 mm.

3 0

4 years ago

Copper is a type of metal.

S_A_V [24]

The temperature rise in the copper is. I think its 0.393

4 0

3 years ago