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My name is Ann [436]
3 years ago
8

Which radiation has no electric charge associated with it?

Physics
1 answer:
joja [24]3 years ago
3 0

Answer:

Gamma radiation

Explanation:

There are three types of ionizing radiation:

- Alpha radiation: it consists of alpha particles, which are nuclei of helium (so, they contain 2 protons and 2 neutron) --> therefore, they have a net charge of +2 (given by the positive charge of the two electrons)

- Beta radiation: it consists of electron (in case of beta-minus radiation) or positrons (in case of beta-plus radiation). Therefore, in both cases the radiation is electrically charged: charge -e for the electrons, charge +e for the positrons

- Gamma radiation: it consists of high-energy photons. Since photons are electrically neutral, gamma radiation has no electric charge associated with it.

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An effort of 200 N is used to lift a load of 800 N by using a lever. If the load is at a distance of 40 cm from the fulcrum then
Alchen [17]

The effort distance​ will be 160 cm.Applying the moment at the center as follows will provide the effort distance:

<h3 /><h3>What is the mechanical advantage?</h3>

Mechanical advantage is a measure of the ratio of output force to input force in a system, it is used to obtain the efficiency of forces in levers and pulleys.

Given data;

Effort,\rm F_e=00 N

Load,\rm P= 400 \ N

Distance from the fulcrum,\rm d=40 \ cm

The effort distance​ is found by applying the moment at the center as;

\rm F_e \times d= P \times  d' \\\\ 200 \  N \times d'=800 \ N \times 40 \ cm \\\\ d'=160 \ cm

Hence, the effort distance​ will be 160 cm

To learn more about the mechanical advantage refer to the link;

brainly.com/question/7638820

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2 years ago
Use this technique to find a formula for the intensity I of a sound, in terms of the sound level β and the reference intensity I
mezya [45]

The problem is basically asking us to find a way to find the sound intensity I, in terms dependent on the sound level and the reference intensity I_0.For this purpose we can start from the unit used in the scale logarithmic decibel, that is

\beta = 10log_{10}\frac{I}{I_0}

Where

I = Acoustic intensity on the linear scale

I_0 = Hearing threshold

Using the logarithmic properties of the exponents the above expression can be described as:

(\frac{I}{I_0})^{10} = 10^{\beta}

I = I_0 10^{\frac{\beta}{10}} \righarrow that is the expression or technique to find the intensity of sound.

8 0
3 years ago
Describe all the ways that newtons laws can apply in a car crash
Harman [31]
Newtons first law - Objects in the car at rest (The human) will remain at rest unless affected by an unbalanced force. Well the unbalanced force would be the crash and this would set the human in motion and they would ether fly out the car if not wearing a seat belt or if wearing one they would get bad whip lash

Newtons second law - With more mass requires more force, so since the human is pretty light or even if heavy in a big crash there will be so much more from it that this will send the human flying.

Newtons 3rd law - Objects A puts force onto objects b and object b excretes the same amount of force back onto object a, so in a crash the human would hit the car hard and the car would excrete the same amount of force back on the human which would really damage him/her
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3 years ago
A Cat is on a balcony floor (90cm below the railing), keenly eyeing a butterfly hovering 60 cm above the railing. With what spee
GenaCL600 [577]

We will have the following:

First, the equation to use is the following:

d=v_ot+\frac{1}{2}at^2

Now, we transform the total distance the cat would need to travel:

90\operatorname{cm}+60\operatorname{cm}=150\operatorname{cm}\cdot\frac{1m}{100\operatorname{cm}}=1.5m

So, the cat would need to travel 1.5 meters. ("d" in the equation).

Now, using the speed given we determine the time it would take the cat to traverse the 1.5 meters:

t=\frac{1.5m\cdot1s}{0.45m}\Rightarrow t=\frac{10}{3}\Rightarrow t=3.333\ldots

So, the time it would take the cat to traverse the distance will be approximately 3.33 seconds.

Now, we know that the acceleration will be given by Earth's gravity, so:

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So, the initial vvelocity the cat must leave the floor in order to arrive at the butterfly with the optimum pouncing speed of 0.45 m/s is approximately 16.78 m/s or exactly 1007/60 m/s.

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What does the dashed line represent in this diagram?
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