Which of the following is the best description of the results of a chemical reaction?

Compare an oxygen particle to a water particle. In your answer , include describing how they are different and similar.

Naddik [55]

Answer:

An oxygen molecule consists of two oxygen (o2) atoms bound together and a water molecule consists of two hydrogen atoms and one oxygen atom (h20). H20 has a higher evaporation temperature than oxygen therefore it stays a liquid at room temperature unlike oxygen. Both have oxygen atoms.

5 0

3 years ago

What is 2000lbs in 1 ton

liq [111]

You've answered your question it is 1 ton

3 0

3 years ago

An empty Erlenmeyer flask weighs 241.3 g. When filled with water (d = 1.00 g/cm³), the flask and its contents weigh 489.1 g.

Viefleur [7K]

The answer is- Mass of flask = 608.04 g

Density (d) is defined as mass of substance divided by its volume. Thus, if mass and density are known, then Volume can be determined.

What is the formula of mass in terms of density?

Let mass of substance be 'm' and volume be 'V'. Thus, as per the definition of density, it is expressed as-

$d = \frac{m}{V}$

Thus, mass can be expressed as-

$m = d * V$

Now, mass of empty flask = 241.3 g and the mass of (flask + Water) = 489.1 g.

Thus, mass of water = $489.1\ g- 241.3\ g = 247.8\ g$ .

Thus, mass of water = 247.8 g and density of water = $1.00\ g/cm^3$ . Its volume is calculated as-

$V = \frac{247.8\ g}{1.00\ g/cm^3}=247.8\ cm^3$

Volume of flask = 247.8 $cm^3$ .
Then when this flask is filled with chloroform (d = $1.48 g/cm^3$ ), the mass of chloroform is-

$m = d * V = (1.48\ g/cm^3) * (247.8\ cm^3)= 366.74\ g$

Hence, the mass of flask becomes = $241.3\ g + 366.74\ g = 608.04\ g$

To learn more about Density and mass, visit:

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4 0

1 year ago

What type of van der Waals interactions occur between molecules

BigorU [14]

Given what we know, we can confirm that the type of van der Waals interactions that occur between molecules of O2, SCl2, and CH4 in liquids of these substances are the presence of <u>London dispersion forces</u>.

<h3>What are London dispersion forces?</h3>

They are a force of attraction between atoms.
They are generated by electrostatic attraction.
These forces are common between atoms in close proximity and occur often when compounds have a symmetrical distribution of atoms.
They are generated by the formation of temporary dipoles.

Therefore, given the symmetry of the atoms disposition in these compounds and the temporary dipoles generated by the atoms being in close proximity, we can confirm that the van der Waals forces present in each compound are London dispersion forces.

To learn more about van deer Waals forces visit:
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7 0

2 years ago

Carbon tetrachloride, CCl4, once used as a cleaning fluid and as a fire extinguisher, is produced by heating methane and chlorin

Elena-2011 [213]

Answer:

1.882 g

Explanation:

Data Given

mass of Cl₂ = 33.4 g

mass of CH₄ = ?

Reaction Given:

CH₄+ 4Cl₂ --------→ CCl₄ + HCl

Solution:

First find the mass of CH₄ from the reaction that it combine with how many grams of Chlorin.

Look at the balanced reaction

CH₄ + 4Cl₂ --------→ CCl₄ + 4HCl

1 mol 4 mol

So 1 mole of CH₄ combine with 4 moles of Cl₂

Now

convert the moles into mass for which we have to know molar mass of CH₄ and Cl₂

Molar mass of Cl₂ = 2 (35.5)

Molar mass of Cl₂ = 71 g/mol

mass of Cl₂

mass in grams = no. of moles x molar mass

mass of Cl₂ = 4 mol x 71 g/mol

mass of Cl₂ = 284 g

Molar mass of CH₄= 12+ 4(1)

Molar mass of CH₄= 16 g/mol

mass of CH₄

mass in grams = no. of moles x molar mass

mass of CH₄= 1 mol x 16 g/mol

mass of CH₄ = 16 g

So,

284 g of Cl₂ combine with 16 g of methane ( CH₄ ) then how many grams of CH₄ is needed to combine with 33.4 g of Cl₂

Apply unity Formula

284 g of Cl₂ ≅ 16 g of methane ( CH₄ )

33.4 g of Cl₂ ≅ X g of methane ( CH₄ )

By cross multiplication

X g of methane ( CH₄ ) = 16 g x 33.4 g / 284 g

X g of methane ( CH₄ ) = 1.88 g

1.882 g of methane (CH₄) will needed to combine with 33.4 g of Cl₂

So

methane (CH₄) = 1.882 g

5 0

3 years ago