Answer:
The concentration of KBr is 
Explanation:
From the question we are told that
The mass of KBr is 
The molar mass of KBr is 
Volume of water is 
This implies that the volume of the solution is 
The number of moles of KBr is
Substituting values
The concentration of KBr is mathematically represented as
The answer is: mass is 40.17 kilograms.
d = 0.758 g/mL; density of fuel.
V = 14.0 gal; volume.
A gallon is a unit of volume in both the US customary and imperial systems of measurement. The US gallon is defined as 231 cubic inches (3.785 liters).
1 gal = 3785.41 mL.
V = 14 gal · 3785.41 mL:
V = 52995.74 mL.
m = 52995.74 mL · 0.758 g/mL.
m = 40170.77 g; mass of fuel.
m = 40170.77 g ÷ 1000 g/kg.
m = 40.17 kg.
Complete question:
ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J. calculate the magnitude of q for the process.
Answer:
The magnitude of q for the process 568 J.
Explanation:
Given;
change in internal energy of the gas, ΔU = 475 J
work done by the gas, w = 93 J
heat added to the system, = q
During gas expansion process, heat is added to the gas.
Apply the first law of thermodynamic to determine the magnitude of heat added to the gas.
ΔU = q - w
q = ΔU + w
q = 475 J + 93 J
q = 568 J
Therefore, the magnitude of q for the process 568 J.
