Question

Kyle and Michael run a lap around a track. Kyle gets a 50 meter head start and runs 3 meters per second. Michael runs at a speed of 4 meters per second. How long will it take for Michael to reach Kyle

Answer 1

Answer:

50 seconds

Step-by-step explanation:

Let x be the distance ( in meters ) from kyle to the point where they meet.

Since,

$Time =\frac{Distance}{Speed}$

For kyle,

Distance = x,

Speed = 3 m/s

So, time taken by Kyle = $\frac{x}{3}$

Now, for Michael,

Distance = (x + 50) ( Because Kyle is 50 meters ahead of Michael )

Speed = 4 m/s

So, time taken by Michael = $\frac{x+50}{4}$

When they meet each other,

$\frac{x}{3}=\frac{x+50}{4}$

$4x=3x+150$

$x=150$

Hence, the time after which they meet = $\frac{150}{3}$ = 50 seconds

Answer 2

First, you need to put both equations in slope intercept form

Kyle: y=3x+50, because he runs 3 meters/second and he gets a 50 meter head start

Michael: y=4x

I think the answer would be 50 seconds

hope this helps