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3 years ago

Solve for x. 13x - 7 = 136

1 answer:

3 0

Add 7 on both sides to then left side cancels out and you end up with 13x=143 then you divide 13 on both sides and get x=11

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Question 5<br> Work out 524 + 344 =

Rainbow [258]

Answer:

868

Step-by-step explanation:

5 2 4

+ 3 4 4

------------

4 + 4 = 8

5 2 4

+ 3 4 4

------------

2 + 4 = 6

5 2 4

+ 3 4 4

------------

6 8

5 + 3 = 8

5 2 4

+ 3 4 4

------------

8 6 8

524 + 344 = 868

Hope this helps.

3 0

3 years ago

Read 2 more answers

Please help ASAP with question 2

Drupady [299]

Answer:

Step-by-step explanation:

y=20+2.8 and got 100%

7 0

2 years ago

Select the condition for which it is NOT possible to construct a triangle. A triangle with side lengths 4 cm, 5 cm, and 6 cm A t

stellarik [79]

Answer:

Option B: A triangle with side lengths 4 cm, 5 cm, and 15 cm

Step-by-step explanation:

Since we are dealing here majorly with sides, one condition is that each side has to be shorter than the sum of the other two sides and longer than their difference meaning that if we have a, b and c

The a value has to be shorter than the sum of b and c - a < b+c and the a value also has to be longer than their difference - a > b-c

In this example,we have side lengths 4 cm, 5 cm, and 15 cm. Taking a, b and c as 4 cm, 5 cm, and 15 cm respectively.

The sum of 5 and 4 is 9 and the third side 15 is greater than 9 when it is supposed to be less to construct a triangle.

6 0

3 years ago

If a fair coin is flipped 15 times, what is the probability that there are more heads than tails?

ludmilkaskok [199]

Answer:

The probability that there are more heads than tails is equal to $\dfrac{1}{2}$ .

Step-by-step explanation:

Since the number of flips is an odd number, there can't be an equal number of heads and tails. In other words, there are either

more tails than heads, or,
more heads than tails.

Let the event that there are more heads than tails be $A$ . $\lnot A$ (i.e., not A) denotes that there are more tails than heads. Either one of these two cases must happen. As a result, $P(A) + P(\lnot A) = 1$ .

Additionally, since this coin is fair, the probability of getting a head is equal to the probability of getting a tail on each toss. That implies that (for example)

the probability of getting 7 heads out of 15 tosses will be the same as
the probability of getting 7 tails out of 15 tosses.

Due to this symmetry,

the probability of getting more heads than tails (A is true) is equal to
the probability of getting more tails than heads (A is not true.)

In other words $P(A) = P(\lnot A)$ .

Combining the two equations:

$\left\{\begin{aligned}&P(A) + P(\lnot A) = 1 \cr &P(A) = P(\lnot A)\end{aligned}\right.$ ,

$P(A) = P(\lnot A) = \dfrac{1}{2}$ .

In other words, the probability that there are more heads than tails is equal to $\dfrac{1}{2}$ .

This conclusion can be verified using the cumulative probability function for binomial distributions with $\dfrac{1}{2}$ as the probability of success.

$\begin{aligned}P(A) =& P(n \ge 8) \cr =& \sum \limits_{i = 8}^{15} {15 \choose i} (0.5)^{i} (0.5)^{15 - i}\cr =& \sum \limits_{i = 8}^{15} {15 \choose i} (0.5)^{15}\cr =& (0.5)^{15} \left({15 \choose 8} + {15 \choose 9} + \cdots + {15 \choose 15}\right) \cr =& (0.5)^{15} \left({15 \choose (15 - 8)} + {15 \choose (15 - 9)} + \cdots + {15 \choose (15 - 15)} \right) \cr =& (0.5)^{15} \left({15 \choose 7} + {15 \choose 6} + \cdots + {15 \choose 0}\right)\end{aligned}$

$\begin{aligned}\phantom{P(A)} =& \sum \limits_{i = 0}^{7} {15 \choose i} (0.5)^{15}\cr =& P(n \le 7) \cr =& P(\lnot A)\end{aligned}$ .

6 0

3 years ago

Help please I need this so much ... <br> I will brainlist

Shtirlitz [24]

The answer this is the 3rd option choice: Reaches a maximum height of 549 feet after 5.75 seconds.

8 0

2 years ago