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marusya05 [52]
3 years ago
11

Solve for x. 13x - 7 = 136

Mathematics
1 answer:
aniked [119]3 years ago
3 0
Add 7 on both sides to then left side cancels out and you end up with 13x=143 then you divide 13 on both sides and get x=11
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A bag contains 6 red balls and blue balls. 4 balls are selected at random. find the probability of selecting 4 red balls.
masya89 [10]

Another way is to note that there are <span><span>(<span>104</span>)</span><span>(<span>104</span>)</span></span> (“10 choose 4”) ways to select 4 balls from a collection of 10. If 4 of those 10 balls are “special” in some way (in this case, “special” = “red”), then the number of ways to choose 4 special balls is <span><span>(<span>44</span>)</span><span>(<span>44</span>)</span></span>. (The factor of <span><span>(<span>60</span>)</span><span>(<span>60</span>)</span></span> is included to convey that, after choosing 4 special balls, we choose none of the 6 non-special balls.) This line of reasoning gives the second expression.

8 0
3 years ago
1 1/2 x -2= <br> PROCESS !!!!
trasher [3.6K]
11/2x=2
2/11(11/2)x=2(2/11)
x=4/11
7 0
3 years ago
Explain how to verify that 3(2x + 5) = 9 + 3x and x = –2 are equivalent equations.
aniked [119]

3 times (2x + 5) is 6x + 15.

6x + 15 = 9 + 3x.

Group by like terms. 6 = -3x

Divide to get x by itself. 6/-3 = -2

Thus -2 = x

6 0
3 years ago
Hi Saige this is Annabel
harina [27]
Absjnwksnekendkoend d points
3 0
3 years ago
Read 2 more answers
Let a_n be the n th digit after the decimal point in
WITCHER [35]
I believe this should just be equal to<span>
9π+5e−<span>(<span>⌊9π+5e⌋</span>)</span>=9π+5e−41</span>
The first element in your sum should be the first digit after the decimal point times .1, so you have
.8
The next element in the sum is the second digit after the decimal place times .01, so you get<span>
.8+.06=.86

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
5 0
3 years ago
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