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3 years ago

What is the value of the σ∗1s mo wave function at the nodal plane?

Chemistry

2 answers:

Paul [167]3 years ago

8 0

Answer:

Refer below.

Explanation:

Therefore,

The σ∗1s mo wave function at the nodal plane value is none.

You need the wave function for the specific orbital, which isn't promptly accessible except if the atom is hydrogen.

Leona [35]3 years ago

5 0

Answer:

There is None

Explanation:

This is because it is a derived function dependent on other factors.

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3 years ago

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2 years ago

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3 years ago

Read 2 more answers

Calculate the standard enthalpy change for the reaction at 25 ∘C. Standard enthalpy of formation values can be found in this lis

weqwewe [10]

Answer:

$\Delta H_{rxn}=-2043.999kJ$

Explanation:

$\Delta H_{rxn}^{0}=\sum [n_{i}\times \Delta H_{f}^{0}(product)_{i}]-\sum [n_{j}\times \Delta H_{f}^{0}(reactant_{j})]$

Where $n_{i}$ and $n_{j}$ are number of moles of product and reactant respectively (equal to their stoichiometric coefficient).

$\Delta H_{f}^{0}$ is standard heat of formation and $\Delta H_{rxn}^{0}$ is standard enthalpy change for reaction at $25^{0}\textrm{C}$

So, $\Delta H_{rxn}=[3mol\times \Delta H_{f}^{0}(CO_{2})_{g}]+[4mol\times \Delta H_{f}^{0}(H_{2}O)_{g}]-[1mol\times \Delta H_{f}^{0}(C_{3}H_{8})_{g}]-[5mol\times \Delta H_{f}^{0}(O_{2})_{g}]$

or, $\Delta H_{rxn}=[3mol\times -393.509kJ/mol]+[4mol\times -241.818kJ/mol]-[1mol\times -103.8kJ/mol]-[5mol\times 0kJ/mol]$

or, $\Delta H_{rxn}=-2043.999kJ$

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4 years ago