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Aleonysh [2.5K]
2 years ago
5

Calculate the volume in L of 12.9 g of NO2 at STP.

Chemistry
1 answer:
d1i1m1o1n [39]2 years ago
3 0

Answer:

6.28 L

Explanation:

Given data:

Volume of NO₂ = ?

Mass of NO₂ = 12.9 g

Temperature and pressure = ?

Solution:

First of all we will calculate the number of moles of gas.

Number of moles = mass/molar mass

Number of moles = 12.9 g/ 46 g/mol

Number of moles = 0.28 mol

At standard temperature and pressure 1 mole of gas occupy 22.4 L volume.

Thus,

0.28 mol × 22.4 L/1 mol

6.27 L ≅ 6.28 L

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<em>The </em><em>specific</em><em> </em><em>heat </em><em>capacity</em><em>=</em><em>quantity</em><em> of</em><em> </em><em>heat</em><em> </em><em>in </em><em>joule/</em><em>mass×</em><em>c</em><em>h</em><em>a</em><em>n</em><em>g</em><em>e</em><em> </em><em>in </em><em>temperature</em>

<em>from </em><em>this </em><em>question</em><em> </em><em>the </em><em>quantity</em><em> of</em><em> </em><em>heat</em><em> </em><em>is </em><em>7</em><em>5</em><em>2</em><em>5</em><em>0</em><em>,</em><em>the </em><em>mass </em><em>is </em><em>2</em><em>0</em><em>0</em><em>0</em><em> </em><em>and </em><em>the </em><em>change </em><em>in </em><em>temperature</em><em> </em><em>is </em><em>5</em><em>0</em><em>-</em><em>3</em><em>0</em>

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<em>c=</em><em>7</em><em>5</em><em>2</em><em>5</em><em>0</em><em>/</em><em>4</em><em>0</em><em>0</em><em>0</em><em>0</em>

<em>c=</em><em>1</em><em>.</em><em>8</em><em>8</em>

<em>I </em><em>hope </em><em>this </em><em>helps</em>

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