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larisa86 [58]
3 years ago
15

Q3. Ishah spins a fair 5-sided spinner. She then throws a fair coin.

Mathematics
1 answer:
balu736 [363]3 years ago
4 0

Answer:

see below

Step-by-step explanation:

1.

1, H - 2, H - 3, H - 4, H - 5, H

1, T - 2, T - 3, T - 4, T - 5, T

2.

2,H is one out of 10 possible outcomes, so the probability is 1/10

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Determine if the graph is symmetric about the x-axis, the y-axis, or the origin.
gulaghasi [49]
This equation is an example of a Limacon with inner loop. By using the symmetry tests where:

POLAR AXIS/HORIZONTAL:
replace a) θ by -θ, b) r by -r and θ by π-<span>θ

VERTICAL AXIS:
replace a) </span>θ by π-θ, b) r by -r and θ by -<span>θ

POLE:
replace a) </span>θ by π+<span>θ, b) r by -r 

If any of these rules, after replacing it in the equation, results to the original equation (making it the equivalent) then it is symmetrical to that axis. 

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4 0
3 years ago
Read 2 more answers
Write an expression that, when simplified is equivalent to 15x +7
cupoosta [38]

Answer:

2(7.5x+3.5)

Step-by-step explanation:

I can't remember what these equations are actually called, however in order to solve this you simply multiply 7.5 by 2, and then 3.5 by 2.

4 0
3 years ago
What are the two solutions of 2x^2 = -X^2 - 5x - 1?
Sidana [21]

Answer:

Step-by-step explanation:

Let's solve 2x^2 = -X^2 - 5x - 1.  Consolidate all terms on the left side and write 0 on the right side:

3x^2 + 5x + 1 = 0.  This is a quadratic equation.  Let's solve it for x using the quadratic formula:

a = 3, b = 5, c = 1, and so the discriminant is b^2 - 4ac = 5^2 - 4(3)(1) = 13.  Because the discriminant is positive, we know that there are two distinct, real roots; the graphs of y = 2x^2 and y = x^2 - 5x - 1 intersect in two places whose x-coordinates are the real roots mentioned above.

Answer A is not correct as stated, but would be correct if we were to replace "the y-coordinates" with "the x-coordinates."  

Answer C would be correct if and only if we write y = x^2 - 5x - 1.

6 0
3 years ago
For the following pair of functions, find (f+g)(x) and (f-g)(x).
ch4aika [34]

Given:

The functions are

f(x)=4x^2+7x-5

g(x)=-9x^2+4x-13

To find:

The functions (f+g)(x) and (f-g)(x).

Solution:

We know that,

(f+g)(x)=f(x)+g(x)

(f+g)(x)=4x^2+7x-5-9x^2+4x-13

(f+g)(x)=(4x^2-9x^2)+(7x+4x)+(-5-13)

(f+g)(x)=-5x^2+11x-18

And,

(f-g)(x)=f(x)-g(x)

(f-g)(x)=(4x^2+7x-5)-(-9x^2+4x-13)

(f+g)(x)=4x^2+7x-5+9x^2-4x+13

(f+g)(x)=(4x^2+9x^2)+(7x-4x)+(-5+13)

(f-g)(x)=13x^2+3x+8

Therefore, the required functions are (f+g)(x)=-5x^2+11x-18

and (f-g)(x)=13x^2+3x+8.

7 0
3 years ago
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