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max2010maxim [7]
3 years ago
8

How many pounds in a 3.00 l bottle of drinking water?

Chemistry
1 answer:
slava [35]3 years ago
6 0

Answer:

             6.61 Pounds

Solution:

Step 1: Calculate Mass of Water as;

                        Density  =  Mass  ÷  Volume

Solving for Mass,

                        Mass  =  Density  ×  Volume   ------ (1)

As,

                        Density of Water  =  1 g.cm⁻³

And,

                        3 L of Water  =  3000 cm³

Putting values in equation 1,

                        Mass  =  1 g.cm⁻³  × 3000 cm³

                        Mass  =  3000 g

Step 2: Convert Grams into Pounds;

As,

                        1 Gram  =  0.002204 Pounds

So,

                        3000 Grams  =  X Pounds

Solving for X,

                      X =  (3000 Grams  ×  0.002204 Pounds)  ÷  1 Gram

                      X =  6.61 Pounds

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