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Rina8888 [55]
2 years ago
15

what is the molarity of a solution prepared by dissolving 1.25g of HCL gas into enough water to make 30cm cube of solution?

Chemistry
1 answer:
Tpy6a [65]2 years ago
4 0
Molars are cavities in your teeth the dentists will scrape them out and fill them in for you at your earliest convinence need help with anything else while im here i can assist you!
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What is the new boiling point if 25 g of NaCl is dissolved in 1.0 kg of water
Inessa05 [86]
The correct answer for the question that is being presented above is this one: 

Given that:
delta Tb = Kbm Kb H2O = 0.52 degrees C/m 
<span>delta Tf = Kfm Kf H2O = 1.86 degrees C/m 
</span>
We need to know the formula for Molality.
molality = mol solute / kg solvent 

<span>We are given the amount of solute in grams
Since amount of solute is given in moles, we have to convert 25 g NaCl to moles. Divide by molar mass. </span>

<span>25 g NaCl / 58.5 g/mol = 0.427 mol </span>

<span>Then, use the formula for molality. </span>

<span>molality = mol solute / kg solvent </span>
<span>= 0.427 / 1 </span>
<span>= 0.427 m </span>

<span>Use now the formula to get the boiling point.</span>

<span>delta Tb = Kbm </span>
<span>= (0.52)(0.427) </span>
<span>= 0.22C </span>
8 0
3 years ago
What is the boiling point of a solution of 76 g of water dissolved in 500 mL of acetic acid, CH3COOH?
tatuchka [14]

Answer:

127.3° C, (This is not a choice)

Explanation:

This is about the colligative property of boiling point.

ΔT = Kb . m . i

Where:

ΔT = T° boling of solution - T° boiling of pure solvent

Kb = Boiling constant

m = molal (mol/kg)

i = Van't Hoff factor (number of particles dissolved in solution)

Water is not a ionic compound, but we assume that i = 2

H₂O →  H⁺  +  OH⁻

T° boling of solution - 118.1°C =  0.52°C . m . 2

Mass of solvent =  Solvent volume / Solvent density

Mass of solvent = 500 mL / 1.049g/mL → 476.6 g

Mol of water are mass / molar mass

76 g / 18g/m = 4.22 moles

These moles are in 476.6 g

Mol / kg = molal → 4.22 m / 0.4766 kg = 8.85 m

T° boling of solution =  0.52°C . 8.85 m . 2 + 118.1°C =  127.3°C

6 0
3 years ago
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Answer:

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