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stellarik [79]
3 years ago
10

The 10x SDS gel electrophoresis buffer contains 250mM Tris HCl, 1.92M Glycine, and 1% (w/v) SDS. Buffers are always used at 1x c

oncentration in the lab (unless specified otherwise in the protocol), so you will have to dilute the 10x buffer to 1x before use. What is the concentration of Tris and SDS in the 1x buffer
Chemistry
1 answer:
olchik [2.2K]3 years ago
7 0

Answer:

25 mM Tris HCl and 0.1% w/v SDS

Explanation:

A <em>10X solution</em> is ten times more concentrated than a <em>1X solution</em>. The stock solution is generally more concentrated (10X) and for its use, a dilution is required. Thus, to prepare a buffer 1X from a 10X buffer, you have to perform a dilution in a factor of 10 (1 volume of 10X solution is taken and mixed with 9 volumes of water). In consequence, all the concentrations of the components are diluted 10 times. To calculate the final concentration of each component in the 1X solution, we simply divide the concentration into 10:

(250 mM Tris HCl)/10 = 25 mM Tris HCl

(1.92 M glycine)/10 = 0.192 M glycine

(1% w/v SDS)/10 = 0.1% w/v SDS

Therefore the final concentrations of Tris and SDS are 25 mM and 0.1% w/v, respectively.

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A sample of mercury has a mass of 607.0 lb and a volume of 0.717 ft. What is its specific gravity? Number SG= What are the units
stepan [7]

Answer:

Specific gravity of mercury is 13.56 and it is an unit-less quantity.

Explanation:

Mass of the mercury = m = 607.0 lb = 275330.344 g

1 lb = 453.592 g

Volume of the mercury  = v = 0.717 ft^3=20,303.18 mL

1 ft^3 = 28316.847 mL

Density of the mercury = d=\frac{m}{v}=\frac{275330.344  g}{20,303.18 mL}

d = 13.56 g/mL

Specific gravity of substance = Density of substance ÷ Density of water

S.G=\frac{d}{1 g/mL}

Specific gravity of mercury :

S.G=\frac{13.56 g/mL}{1 g/mL}=13.56 (unit-less quantity)

5 0
3 years ago
What do the elements in each pair have in common?
disa [49]

The elements in each pair have in common it that they are metaloids

7 0
3 years ago
The correct mathematical expression for finding the molar solubility (s) of calcium phosphate is
GalinKa [24]

Answer is: The molar solubility of calcium phosphate is 108s⁵ = Ksp.

<span> Balanced chemical reaction: Ca</span>₃(PO₄)₂(s) → 3Ca²⁺(aq) + 2PO₄³⁻(aq).<span>
[Ca²</span>⁺] = 3s(Ca₃(PO₄)₂) = 3s.<span>
[PO</span>₄³⁻] = 2s.<span>
Ksp = [Ca²</span>⁺]³ · [PO₄³⁻]².<span>
Ksp = (3s)³ · (2s)².
Ksp = 108s</span>⁵.

s = ⁵√(Ksp ÷ 108).

6 0
3 years ago
The length breadth and thickness of a brick is 18cm 8 cm and 5cm respictively find the area of the widest part of rhe brick​
Sunny_sXe [5.5K]

Answer:

144cm²

Explanation:

Given dimensions:

     Length x breadth x thickness

        18cm  x   8cm    x    5cm

The widest part of this figure will be the face containing the length and the breadth.

The breadth is the width of the figure;

Area of the widest part  = length x breadth = 18cm x 8cm  = 144cm

The area of the widest part of the figure is 144cm²

4 0
3 years ago
CHEM HELP PLZZZZ!!!!!
earnstyle [38]

Answer:

1. acid

2. neutral

3. acid

4. base

5. acid

6. base

7. neutral

8. acid

9. base

10. base

Explanation:

I'm not 100 percent positive about number three but the rest I believe are correct

3 0
2 years ago
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