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Softa [21]
3 years ago
8

How would local winds be affected if water and land release heat at the same time

Physics
1 answer:
BlackZzzverrR [31]3 years ago
8 0
Local winds are driven by temperature differences in areas fairly close to each other. If water and land absorbed and released heat at the same rate, there wouldn't be any temperature differences and nothing to power local winds. See the related link for further information.
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An object has 16N of force being applied to the right, 16N of force being applied to the left, and 4N of force being applied dow
goldenfox [79]

Answer:

4N downward

Explanation:

the 16N left and right cancel each other out, so you are left with the 4N downward.

6 0
3 years ago
Name two specific contributions bohr made to our understanding of atomic structure
MAXImum [283]
Https://answers.yahoo.com/question/index?qid=20120227184717AAzEq8g
6 0
3 years ago
Planets A and B have the same mass, but planet A is half the size of planet B.
pychu [463]

Answer:

c. You would weigh less on planet A because the distance between

you and the planet's center of gravity would be smaller.

Explanation:

The statement that best describes your weight on each planet is that you would weigh less on planet A because the distance between you and the planet's center of gravity would be smaller.

  • This is based on Newton's law of universal gravitation which states that "the force of gravity between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distances between them".

Since weight is dependent on the force of gravity and mass, the planet with more gravitational pull will have masses on them weighing more.

  • Since the distance between the person and the center of the planet is smaller, therefore, the weight will be lesser.
7 0
3 years ago
Read 2 more answers
Two ions with masses of 4.39×10−27 kg move out of the slit of a mass spectrometer and into a region where the magnetic field is
Ilia_Sergeevich [38]

Answer:

7.2 cm

Explanation:

magnetic field, B = 0.301 T

speed, v = 7.92 x 10^5 m/s

mass, m = 4.39 x 10^-27 kg

q = 1.6 x 10^-19 C

The radius of singly changed ion is given by

r = \frac{mv}{Bq}

where, m is the mass of ion, v be the speed of ion, B is the magnetic field and q be the charge

r = \frac{4.39\times 10^{-27}\times 7.92 \times 10^{5}}{0.301\times 1.6\times 10^{-19}}

r = 0.072 m

r = 7.2 cm

5 0
3 years ago
A 60 N force is applied over a distance of 15 m. How much work was done?
GuDViN [60]

Answer:

900J

Explanation:

w =f×s

60×15

=900J

thus the k.e of the body is 900j

3 0
2 years ago
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