All categories

2 years ago

Calculate the mass of a block of ice having volume 5 m cube. (density of ice= 920 kg/m cube)

Physics

1 answer:

GarryVolchara [31]2 years ago

5 0

Answer:

$\huge\pink{\mid{\fbox{\tt{your\:answer}}\mid}}$

${\large{\red{\mapsto{\maltese{\underline{\green{\boxed{\blue{\underbrace{\overbrace{\pink{\pmb{\bf{i \: hope \: it \: help \: you:}}}}}}}}}}}}}}$

You might be interested in

What are the limitations of using solar panels?

umka21 [38]

Location & Sunlight Availability.
Solar Panels use a large amount of space.
The Sun isn't always present.
Solar Energy is Inefficient.
There is an overlooked Pollution & Environmental Impact.
Expensive Energy Storage.
High Initial Cost.

8 0

2 years ago

An airplane touches down on the runway with a speed of 70 m/s2. Determine the airplane after each second of its deceleration.

ivann1987 [24]

<span>vf^2 = vi^2 + 2*a*d
---
vf = velocity final
vi = velocity initial
a = acceleration
d = distance
---
since the airplane is decelerating to zero, vf = 0
---
0 = 55*55 + 2*(-2.5)*d
d = (-55*55)/(2*(-2.5))
d = 605 meters

</span>

5 0

3 years ago

13. Determine the kinetic energy of a 2000g roller coaster car that is moving with a speed of 2m/s.

zubka84 [21]

Answer:

4 Joules (if you mean 2000 grams)

4000 Joules (if you mean 2000 kilograms)

Explanation:

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>

8 0

2 years ago

What is the definition of motivation?

elixir [45]

Motivation is an encouragement to do or achieve something

5 0

3 years ago

Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field

Katyanochek1 [597]

Complete question:

Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field strength at the midpoint between the two rings ?

Answer:

The electric field strength at the mid-point between the two rings is zero.

Explanation:

Given;

diameter of each ring, d = 10 cm = 0.1 m

distance between the rings, r = 21.0 cm = 0.21 m

charge of each ring, q = 40 nC = 40 x 10⁻⁹ C

let the midpoint between the two rings = x

The electric field strength at the midpoint between the two rings is given as;

$E_{mid} = E_{right} +E_{left}\\\\E_{right} = \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } \\\\E_{leftt} = -\ \frac{KQ}{(x^2 + r^2)^\frac{2}{3} }\\\\E_{mid} = \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } - \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } = 0$

Therefore, the electric field strength at the mid-point between the two rings is zero.

7 0

2 years ago

Calculate the mass of a block of ice having volume 5 m cube. (density of ice= 920 kg/m cube)​

Calculate the mass of a block of ice having volume 5 m cube. (density of ice= 920 kg/m cube)