An experimental design is used to assign variables for testing. In contrast to a control design where nothing is changed, the experimental design allows you to test various new inputs to see how they would vary from the original results.
We use the formula,
![h= ut- 16 t^2](https://tex.z-dn.net/?f=h%3D%20ut-%2016%20t%5E2)
Here, h is the variable represents the height of the flare in feet when it returns to the sea so, h = 0 and u is the initial velocity of the flare, in feet per second and its value of 192 ft/sec.
Substituting these values in above equation, we get
.
Here, t= 0 neglect because it is the time when the flare is launched.
Thus, flare return to the sea in 12 s.
The magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N
<h3>What is magnetic force?</h3>
Magnetic force, attraction or repulsion that arises between electrically charged particles because of their motion.The magnitude of the magnetic force acting on the charge is given by:
![\rm F=qvBsin\theta](https://tex.z-dn.net/?f=%5Crm%20F%3DqvBsin%5Ctheta)
where
The magnitude of the charge ![q=5.7\ \mu C =5.7\times 10^{-6} \ C](https://tex.z-dn.net/?f=q%3D5.7%5C%20%5Cmu%20C%20%3D5.7%5Ctimes%2010%5E%7B-6%7D%20%5C%20C)
The velocity of the charge ![v=4.5\times 10^5\ \frac{m}{s}](https://tex.z-dn.net/?f=v%3D4.5%5Ctimes%2010%5E5%5C%20%5Cfrac%7Bm%7D%7Bs%7D)
The magnitude of the magnetic field ![3.2\ mT=0.0032\ T](https://tex.z-dn.net/?f=3.2%5C%20mT%3D0.0032%5C%20T)
The angle between the directions of v and B ![\theta =90^o-37^o=53^o](https://tex.z-dn.net/?f=%5Ctheta%20%3D90%5Eo-37%5Eo%3D53%5Eo)
By substituting the values we will get:
![F=(5.7\times 10^}-6})(4.5\times 10^5)(0.0032)(Sin53^o)](https://tex.z-dn.net/?f=F%3D%285.7%5Ctimes%2010%5E%7D-6%7D%29%284.5%5Ctimes%2010%5E5%29%280.0032%29%28Sin53%5Eo%29)
![F=6.6\times 10^{-3}\ N](https://tex.z-dn.net/?f=F%3D6.6%5Ctimes%2010%5E%7B-3%7D%5C%20N)
Hence the magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N
To know more about Magnetic force follow
brainly.com/question/14411049
Answer:
31.25 m
25m/sec
Explanation:
Given :-
Time = 5sec
V = 0 (in going up)
U = 0 (in comming down)
Find :-
H and U by which it is thrown up
Since the total time is 5 sec ,therefore half time will be taken to go up and another half will be taken to go down .
We know that ,
V = U + gt
0 = U - 10*2.5
U = 25 m/sec
Also,
V² = U² +2gs
0 = 625 - 20s
s = 625/20 = 31.25 m
I would say the last option, since with an increase in temperature, water molecules will speed up.