All categories

3 years ago

When you jump upwards, why don't you notice the Earth moving downwards?

Physics

1 answer:

mixer [17]3 years ago

6 0

Becuase Gravity. The Earthp pulls you down, you do not pull the earth.

You might be interested in

a 12000.0-kg car is traveling at 19 m/s. the driver suddenly slams on the brakes and skids to a stop. The coefficient of kinetic

tensa zangetsu [6.8K]

What I don’t get it ?

6 0

3 years ago

driving down the highway , you find yourself behind a heavily loaded tomato truck. you follow close behind the truck keeping the

prohojiy [21]

Answer:

The tomato won't hit the car

Explanation:

According to the statement, the car moves at constant speed behind the truck fully loaded with tomatoes, and in the same direction. When a tomato falls from the top of the truck, it should not hit the car as the tomato falls due to the force of gravity, while horizontally has the same speed and in the same direction as the truck. So we assume that the tomato will fall to the road without touching the car.

Have a nice day!

4 0

4 years ago

Question 4 of 10

Alexus [3.1K]

Answer:

22.3 kg•m/s

Explanation:

Apex;)

7 0

3 years ago

I am starting out as a pilot. What single engine make of airplane should I get (Cheaper to bye one and train than to rent it)?

hichkok12 [17]

You have to make sure you know what your doing plus if you have your license and stuff to fly you have to practice on a 25 minute course

7 0

3 years ago

Read 2 more answers

A toy car having mass m = 1.50 kg collides inelastically with a toy train of mass M = 3.60 kg. Before the collision, the toy tra

baherus [9]

Answer:

$v_{f}$ = 3,126 m / s

Explanation:

In a crash exercise the moment is conserved, for this a system formed by all the bodies before and after the crash is defined, so that the forces involved have been internalized.

the car has a mass of m = 1.50 kg a speed of v1 = 4.758 m / s and the mass of the train is M = 3.60 kg and its speed v2 = 2.45 m / s

Before the crash

p₀ = m v₁₀ + M v₂₀

After the inelastic shock

$p_{f}$ = m $v_{1f}$ + M $v_{2f}$

p₀ = $p_{f}$

m v₀ + M v₂₀ = m $v_{1f}$ + M $v_{2f}$

We cleared the end of the train

M $v_{2f}$ = m (v₁₀ - v1f) + M v₂₀

Let's calculate

3.60 v2f = 1.50 (2.15-4.75) + 3.60 2.45

$v_{2f}$ = (-3.9 + 8.82) /3.60

$v_{2f}$ = 1.36 m / s

As we can see, this speed is lower than the speed of the car, so the two bodies are joined

set speed must be

m v₁₀ + M v₂₀ = (m + M) $v_{f}$

$v_{f}$ = (m v₁₀ + M v₂₀) / (m + M)

$v_{f}$ = (1.50 4.75 + 3.60 2.45) /(1.50 + 3.60)

$v_{f}$ = 3,126 m / s

4 0

4 years ago