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Mila [183]
3 years ago
15

When you jump upwards, why don't you notice the Earth moving downwards?

Physics
1 answer:
mixer [17]3 years ago
6 0

Becuase Gravity. The Earthp pulls you down, you do not pull the earth.

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Two cylinders each contain 0.30 mol of a diatomic gas at 320 K and a pressure of 3.0 atm. Cylinder A expands isothermally and cy
Svetllana [295]

Answer :

(a). The final temperature of the gas in the cylinder A is 320 K.

(b). The final temperature of the gas in the cylinder B is 233.7 K.

(c). The final volume of the gas in the cylinder A is 7.86\times10^{-3}\ m^3

(d). The final volume of the gas in the cylinder B is 5.7\times10^{-3}\ m^3

Explanation :

Given that,

Number of mole n = 0.30 mol

Initial temperature = 320 K

Pressure = 3.0 atm

Final pressure = 1.0 atm

We need to calculate the initial volume

Using formula of ideal gas

P_{1}V_{1}=nRT

V_{1}=\dfrac{nRT}{P_{1}}

Put the value into the formula

V_{1}=\dfrac{0.30\times8.314\times320}{3.039\times10^{5}}

V_{1}=2.62\times10^{-3}\ m^3

(a). We need to calculate the final temperature of the gas in the cylinder A

Using formula of ideal gas

In isothermally, the temperature is not change.

So, the final temperature of the gas in the cylinder A is 320 K.

(b). We need to calculate the final temperature of the gas in the cylinder B

Using formula of ideal gas

T_{2}=T_{1}\times(\dfrac{P_{1}}{P_{2}})^{\frac{1}{\gamma}-1}

Put the value into the formula

T_{2}=320\times(\dfrac{3}{1})^{\frac{1}{1.4}-1}

T_{2}=233.7\ K

(c). We need to calculate the final volume of the gas in the cylinder A

Using formula of volume of the gas

P_{1}V_{1}=P_{2}V_{2}

V_{2}=\dfrac{P_{1}V_{1}}{P_{2}}

Put the value into the formula

V_{2}=\dfrac{3\times2.62\times10^{-3}}{1}

V_{2}=0.00786\ m^3

V_{2}=7.86\times10^{-3}\ m^3

(d). We need to calculate the final volume of the gas in the cylinder B

Using formula of volume of the gas

V_{2}=V_{1}(\dfrac{P_{1}}{P_{2}})^{\frac{1}{\gamma}}

V_{2}=2.62\times10^{-3}\times(\dfrac{3}{1})^{\frac{1}{1.4}}

V_{2}=0.0057\ m^3

V_{2}=5.7\times10^{-3}\ m^3

Hence, (a). The final temperature of the gas in the cylinder A is 320 K.

(b). The final temperature of the gas in the cylinder B is 233.7 K.

(c). The final volume of the gas in the cylinder A is 7.86\times10^{-3}\ m^3

(d). The final volume of the gas in the cylinder B is 5.7\times10^{-3}\ m^3

6 0
3 years ago
What are the inner planets relative distance from the Sun
Inessa [10]
Closer than the outer planets, inside the Asteroid Belt between Mars and Jupiter.
5 0
3 years ago
Read 2 more answers
Why wil an ice cube melt if it is compressed even if it remains at the same temp
Gnoma [55]
No, it will only melt if the temperature is lowered. If you compress it, it will change the shape, but it will not change the state it is in (i.e. solid).
8 0
3 years ago
PLEASE HELP ME WITH THIS ONE QUESTION
Vlad [161]

Answer: 7.95^{\circ}C

Explanation:

Given

Mass of water is m_1=1\ kg

mass of ice is m_2=0.1\ kg

Latent heat of fusion L=3.33\times 10^5\ kJ/kg

The heat capacity of water is c_{w}=4186\ J/kg^{\circ}C

Suppose water is at  T^{\circ} C  and it reaches to 0^{\circ}C to melt the ice

the heat released by water must be equivalent to heat absorbed by the ice

\therefore \quad m_1c_w(T-0)=m_2\times L\\\Rightarrow 1\times 4186\times T=0.1\times 3.33\times 10^5\\\Rightarrow T=7.95^{\circ}C

6 0
2 years ago
How much heat is required to warm 122 g of water by 23.0 c?
GaryK [48]
<span>122 g * 4,186 (j/g*°c) * 23°c = 11745.916 j </span>
4 0
3 years ago
Read 2 more answers
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