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3 years ago

31/6 as a mixed number

2 answers:

5 0

Hello there awesome brainly user!

To convert $\frac{31}{6}$ to a mixed number you have to divide 31/6 which equals 5 R 1 Remember that the remainder is the numerator and the whole number is 5. So, the mixed fraction is $5\frac{1}{6}$

For further info, message me

Thanks and have a good day.

Romashka-Z-Leto [24]3 years ago

5 0

5 and 1/6 because 5x6=30 plus you have the remainder 1 and 6 is the denominator so the 1 becomes the numerator

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I forgot how to do this in middle school_

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3 years ago

If x+y/y =13, what is the value of y/x?

Montano1993 [528]

$\dfrac{x+y}{y}=13\\\\\dfrac{x}{y}+\dfrac{y}{y}=13\\\\\dfrac{x}{y}+1=13\ \ \ |-1\\\\\dfrac{x}{y}=12\to\dfrac{y}{x}=\dfrac{1}{12}$

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3 years ago

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4+ (-3) - 2*(-6)<br> What is the answer to

konstantin123 [22]

Answer:

Step-by-step explanation:

4+(-3)-2*(-6)

4-3-2*-6

1-(-12)

1+12

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3 years ago

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The Students' Conjectures Emily and Zach have two different polynomials to multiply: Polynomial product A: (4x2 – 4x)(x2 – 4) Po

noname [10]

Complete Question:

Emily and Zach have two different polynomials to multiply: Polynomial product A: (4x2 – 4x)(x2 – 4) Polynomial product B: (x2 + x – 2)(4x2 – 8x) They are trying to determine if the products of the two polynomials are the same. But they disagree about how to solve this problem.

Answer:

$A = B$

Step-by-step explanation:

<em>See comment for complete question</em>

Given

$A: (4x^2 - 4x)(x^2 - 4)$

$B: (x^2 + x - 2)(4x^2 - 8x)$

Required

Determine how they can show if the products are the same or not

To do this, we simply factorize each polynomial

For, Polynomial A: We have:

$A: (4x^2 - 4x)(x^2 - 4)$

Factor out 4x

$A: 4x(x - 1)(x^2 - 4)$

Apply difference of two squares on x^2 - 4

$A: 4x(x - 1)(x - 2)(x+2)$

For, Polynomial B: We have:

$B: (x^2 + x - 2)(4x^2 - 8x)$

Expand x^2 + x - 2

$B:(x^2 + 2x - x - 2)(4x^2- 8x)$

Factorize:

$B:(x(x + 2) -1(x + 2))(4x^2- 8x)$

Factor out x + 2

$B:(x -1) (x + 2)(4x^2- 8x)$

Factor out 4x

$B:(x -1) (x + 2)4x(x- 2)$

Rearrange

$B: 4x(x - 1)(x - 2)(x+2)$

The simplified expressions are:

$A: 4x(x - 1)(x - 2)(x+2)$ and

$B: 4x(x - 1)(x - 2)(x+2)$

Hence, both polynomials are equal

$A = B$

3 0

3 years ago

I don't remember what it is that I'm doing, as I did the lessons before spring break. Help?

blsea [12.9K]

Extraneous solutions, is answers that we get because of squaring both sides of the radical equation, but in reality, they are not going to be the solutions of the given equation.
(√(4x+41))²=(x+5)²
4x+41=x²+10x+25
x²+6x-16=0
(x-2)(x+8)=0
x1=2 , x2=-8,
And now we must to check them by substitution into initial equation

√(4x+41)=x+5
1) x=2, √(4*2+41)=2+5, √49=7, 7=7 true
2) x=-8, √(4*(-8)+41)=-8+5, √9 =-3 false,
so an extraneous solution x=-8

6 0

3 years ago