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3 years ago

If I was to slice this snap in half what two-dimensional shape would it be ?

Mathematics

1 answer:

Lilit [14]3 years ago

8 0

For the rectangular prism, it would be a rectangle and for the sphere it would be a circle

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I need help with this I don’t understand.

liubo4ka [24]

Answer:

the added degree of m1 and m2 equal m4

4 0

3 years ago

Sin^22x - 2cos2x + 2=0

zhuklara [117]

Answer:

x=πn, n∈Z

Step-by-step explanation:

if sin²2x=1-cos²2x, then

1-cos²2x-2cos2x+2=0; ⇒ cos²2x+2cos2x-3=0; ⇔ (cos2x+3)(cos2x-1)=0;

$\left[\begin{array}{cc}cos2x+3=0\\cos2x-1=0\\\end{array} \ \ \left[\begin{array}{cc}x \ 'does-not-exist'\\cos2x=1\\\end{array} \ \ 2x=2\pi n, n=Z \ x=\pi n, n=Z$

5 0

3 years ago

Given f(x) = 2x + 5 and g(x) = 3x + 6

Kryger [21]

I hope this helps you

f(8)=2.8+5=21

g(8)=3.8+6=30

f-g(8)=21-30= -9

6 0

4 years ago

Read 2 more answers

The square of X varies inversely as the square root of Y and directly as the variable M. When M = 27 and Y = 16, then X = 9. Fin

irakobra [83]

Answer:

$Y = 441$

Step-by-step explanation:

Given

M = 27 when Y = 16 and X = 9

Required

Find Y when M = 7 and X = 2

We start by getting the algebraic representation of the given statement

$X^2 \alpha \frac{1}{\sqrt Y} \alpha M$

Convert the variation to an equation; we have

$X^2 = \frac{KM}{\sqrt Y}$

<em>Where K is the constant of variation;</em>

When M = 27; Y = 16; X = 9, the expression becomes

$9^2 = \frac{K * 27}{\sqrt{16}}$

This gives

$81 = \frac{k * 27}{4}$

Make K the subject of formula

$K = \frac{81* 4}{27}$

$K = \frac{324}{27}$

$K = 12$

Solving for Y when M = 7 and X = 2

Recall that $X^2 = \frac{KM}{\sqrt Y}$

Substitute values for K, M and X

$2^2 = \frac{12 * 7}{\sqrt{Y}}$

$4 = \frac{84}{\sqrt{Y}}$

Take square of both sides

$4^2 = (\frac{84}{\sqrt{Y}})^2$

$16 = \frac{7056}{Y}$

Make Y the subject of formula

$Y = \frac{7056}{16}$

$Y = 441$

3 0

3 years ago

Y= 3x^2 + 24x + 10<br> 3x+y=10

Anton [14]

The will be answer is 132

6 0

3 years ago