Answer:
x(t) = 581.66 lb
Step-by-step explanation:
From the given information:
Consider the salt quantity in the tank at time t be x(t) lb.
∴ the rate of change of salt content in the tank is 
where:
the rate of inflow = salt conc. × flow rate = 3 lb/gallon × 7 gallons
=21 lb/s
rate of outflow = salt conc. in the tank × flow rate
= x/250 × 9
= 9x/250 lb/s
∴


This is a 1st order linear differentiation,
The integrating factor if 
∴


at t = (0) and x(0) = 100 lb
Hence;



∴
after time t = 1 minute i.e 60 s


x(t) = 581.66 lb
I think the answer is d because when you multiply you get 60 but with the zero there it would be 59
In order for two lines to be parallel, they must have the dame slope. In this case, it is 7/6. So the new line Will have the next form:
y = 7/6x + b
Now, assuming that the new line passes through the point (1,1):
1 = 7/6*1 + b
b = -0.17
Replacing b:
y = 7/6x - 0.17
Answer:

Step-by-step explanation:
