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cupoosta [38]
3 years ago
14

Consider a study collecting data from a population with an unknown mean and standard deviation. If the sample mean and sample st

andard deviation are the same, what is the effect of increasing the sample size on the following measures? The measure can increase, decrease, not change, or more information may be needed.
Mathematics
1 answer:
Levart [38]3 years ago
8 0

Answer:

Step-by-step explanation:

Increasing the sample size in a particular study will bring about a decrease in the standard deviations of the means.

A decrease in the sample size for a particular study will bring about an increase in the standard deviations of the means.

Whereas the population mean of the distribution of sample means is the same as the population mean of the distribution being sampled from meaning that the population of the distribution of sample means never changes.

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PLZ HELP ME
avanturin [10]

Answer:

D

Step-by-step explanation:

Lengths:

WX: 2

XY: 2

WY: sqrt[(4-2)² + (2-4)²]

sqrt(4+4)

4sqrt(2)

W'(8, 16), X'(8, 8), Y'(16, 8)

W'X': 8 --> 4 × 2

X'Y': 8 --> 4 × 2

W'Y': sqrt[(16-8)² + (8-16)²]

sqrt(64 + 64)

8sqrt(2) --> 4 × 2sqrt(2)

D is a dilation with factor 4

5 0
3 years ago
1. Kyle is using elimination to solve the system
Andrei [34K]
I think it’s D but I am not sure
7 0
3 years ago
Solve This question for Me please I’ll give you brainliest
Lostsunrise [7]

Answer: I believe its the 3rd one

Step-by-step explanation: Because it's less than 97

5 0
3 years ago
Ancient paintings were found on cave walls in South America. The Carbon-14 in the paintings was measured and was found to be 19%
balu736 [363]

Answer: C. 13,839 (the answer is not among the given options, however the result is near this value)

Step-by-step explanation:

The exponential decay model for Carbon- 14 is given by the followig formula:

A=A_{o}e^{-0.0001211.t}  (1)

Where:

A is the final amount of Carbon- 14  

A_{o}= is the initial amount of Carbon- 14

t is the time elapsed (the value we want to find)

On the other hand, we are told the current amount of Carbon-14 A  is 19\%=0.19, assuming the initial amount of Carbon-14 A_{o}= is  100\%:

A=0.19A_{o} (2)

This means: \frac{A}{A_{o}}=0.19 (2)

Now,finding t from (1):

\frac{A}{A_{o}}=e^{-0.0001211.t}  (3)

Applying natural logarithm on both sides:

ln(\frac{A}{A_{o}})=ln(e^{-0.0001211.t})  (4)

ln(0.19)=-0.0001211.t  (5)

t=\frac{ln(0.19)}{-0.0001211}  (6)

Finally:

t=13713.717years  This is the age of the paintings and the option that is nearest to this value is C. 13839 years

6 0
3 years ago
Please help<br>are these functions or not?​
crimeas [40]

Answer:

1. Function

2. Not a function

3. Function

4. Not a function

Step-by-step explanation:

A function just means that for each input it outputs only 1 output. This output isn't necessarily unique. So for example if you're just given: f(2) = 3 and f(1) = 3, this is a function since each input only outputs 1 value, even though the output isn't unique, but if you're given: f(3) = 2, f(2) = 1, f(3) = 3. that's not a function since f(3) outputs both 2 and 3.

Anyways now that you hopefully understand this, let's look at each image.


Relation 1: (Function)

   So for each input (the domain) it's only pointing to one output (range), even if multiple input (the domain) are pointing to the same output (the range), it's still a function.

Relation 2: (Not a function)

   This is not a function, since if you look at the input 7 (the range), you'll see it outputs two things (range). It outputs -6 and -7. So this is not a function

Relation 3: (Function)

   This is a function since each x-value (input) has only one y-value (output). So it's a function

Relation 4: (Not a functio)

   This is not a function, since there are multiply coordinates with the same x-coordinate (input) and different y-coordinates (output). The x-coordinate 2 has the output b, y, and m, and since no value is given for these variables, it can be assumed they're different values, thus it's not a function.

5 0
1 year ago
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