I need help with this!!

Mathematics

2 answers:

Aleksandr [31]2 years ago

5 0

Answer:

i think c

Step-by-step explanation:

hope it helps :)

kozerog [31]2 years ago

5 0

The question is really asking what the slope (m) of the line is. Here’s the answer:

Slope= the variable m

m=rise/run; m=change in y/change in x

We need to find the rate of how much the taxi driver charges per minute.

Therefore:

We need to pick a precise point on the line ( a precise point is a point with whole number x and y coordinates; no decimals or fractions).

We see that the point (6, 9) is precise.

A rate is a ratio in the form of a fraction that shows the relationship of change between two quantities: a/b.

So, the taxi costs 9 dollars / 6 minutes.

9/6 simplifies 2/3.

And thus, the taxi charges 2 dollars per 3 minutes

So, the answer is 9/6, which can be simplified to the furthest possibility, making it a unit rate.

Answer: 9/6

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kvv77 [185]

Answer:

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Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .