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hram777 [196]
3 years ago
15

50 points / will mark BRAINLIEST IF ANSWERED quickly!

Chemistry
1 answer:
liberstina [14]3 years ago
4 0

Answer:

1. density-dependent factors - competition, predation, parasitism, and    disease.

density-independent factors- natural disasters, seasonal cycles, unusual weather, and human activity

2.

As populations increase in size, completion increase as well. For example more people more food demands. as populations become larger and more and more crowded people compete for food, water, sunlight, spaces to live and so on.

3.

Example:

A prolonged drought, with its associated crop loss could cause deaths, financial hardship, and emigration to other areas.

4.

both are under pressure to change in ways that reduce competition, may evolve to occupy different niches

5.

parasites take nourishment from a host - weakening it / killing it

6.

favorable conditions: agriculture, medicine, industry, sanitation

7.

It equal age distribution = very slow, steady growth

large % of children and teenagers = very rapid growth

8.

the recourse may be a part of a organism's niche/habitat (ex. panda and bamboo)

9.

Density (d) depends upon the mass (m) and volume (v) of a substance. The mass depends upon the amount of matter in a substance, whereas volume is the amount of space that a substance takes up.

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Assign an oxidation number to each atom in the products.
Rzqust [24]
<h3>Answer:</h3>

Oxidation number refers to a number given to an atom which shows the number of number of electrons lost (or gained, if the number is negative), by an atom of that element in the compound.

Hence oxidation number of following atoms in given reaction are:

In NaOH:

Na = +1

O = -2

H = +1

In H2:

H = 0


8 0
3 years ago
Read 2 more answers
Help!
podryga [215]
I’m pretty sure it’s 7.5 (7 and a half hours) sorry if i’m wrong
3 0
3 years ago
When K- and I- combine
Charra [1.4K]

Answer:

was zum Teufel

Explanation:

7 0
3 years ago
Calculate the fractional saturation for hemoglobin when the partial pressure of oxygen is 40 mm Hg. Assume hemoglobin is 50%% sa
kumpel [21]

Answer:

The fractional saturation for hemoglobin is 0.86

Explanation:

The fractional saturation for hemoglobin can be calculated using the formula

Y_{O_{2} } = \frac{(P_{O_{2} })^{h}  } {(P_{50})^{h}  + (P_{O_{2} })^{h}   }

Where Y_{O_{2} } \\ is the fractional oxygen saturation

{P_{O_{2} } is the partial pressure of oxygen

P_{50} is the partial pressure when 50% hemoglobin is saturated with oxygen

and h is the Hill coefficient

From the question,

{P_{O_{2} } = 40 mm Hg

P_{50} = 22 mm Hg

h = 3

Putting these values into the equation, we get

Y_{O_{2} } = \frac{(P_{O_{2} })^{h}  } {(P_{50})^{h}  + (P_{O_{2} })^{h}   }

Y_{O_{2} } = \frac{40^{3} }{22^{3} + 40^{3}  }

Y_{O_{2} } = \frac{64000 }{10648 + 64000  }

Y_{O_{2} } = \frac{64000 }{74648 }

Y_{O_{2} } = 0.86

Hence, the fractional saturation for hemoglobin is 0.86.

4 0
3 years ago
How many grams of mgo are produced when 40.0 grams of o2 react completely with mg? 2 mg (s) + o2 (g) → 2 mgo (s)?
SSSSS [86.1K]

Answer: -

100 grams

Explanation: -

Mass of Oxygen = 40 g

Chemical formula of oxygen gas = O2

Molar mass of oxygen = 16 x 2 = 32 gram

Atomic mass of Mg = 24g

Molar mass of MgO = 24 x 1 + 16 x 1 =40 gram

The balanced chemical equation for the reaction is

2Mg + O2 -- > 2 MgO

So from the balanced equation we see that 1 O2 react to give 2 MgO

32 grams of O2 react to give 2 x 40 gram of MgO

40 grams of O2 react to give \frac{2 x 40 gram x 40 gram}{32 gram}

=100 gram of MgO

8 0
3 years ago
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