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3 years ago

14

△DEF is rotated about point N to △D′E′F′ .

1 answer:

MatroZZZ [7]3 years ago

6 0

the answer is d the image is the same size

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11. GARDEN Emily calculates that the area of a flower garden is 28.125. She measured

Svetlanka [38]

Answer:

A=28.13 Sq Ft

Step-by-step explanation:

Given that the length of the garden = 4.5 ft

Breadth of the garden = 6.25 ft

Area is given by the formula

A=length x breadth

A=4.5 x 6.25 sq ft

A= 28.125 sq ft

Here if we round the area to the nearest hundredth, the area will be

A=28.13 Sq Ft

7 0

3 years ago

What is the area of a regular hexagon with a side length of 6 yd? Enter your answer in the box. Round only your final answer to

tatuchka [14]

Your answer would be 93.53

5 0

3 years ago

Read 2 more answers

Find the missing angle.

Sphinxa [80]

Answer:

$m\angle XYV=135^{\circ}$

Step-by-step explanation:

Notice that $m\angle XYV=m\angle XYW+m\angle VYW$ .

The diagram already marks $m\angle VYW=80^{\circ}$ , so we just need to find $m\angle XYW$ .

$\angle TYU$ and $\angle XYW$ are vertical angles, which means they are equal in measure.

Therefore,

$m\angle TYU=m\angle XYW=6x+7$

Since there are $180^{\circ}$ on each side of a line, we have the following equation:

$m\angle XYW+m\angle VYW+m\angle UYV=180^{\circ},\\6x+7+13+4x+80=180,\\10x+20=100,\\10x=80,\\x=8$ .

Plugging in $x=8$ , we have:

$m\angle XYW=6(8)+7=55^{\circ}$ .

Therefore,

$m\angle XYV=55^{\circ}+80^{\circ},\\m\angle XYV=\fbox{$135^{\circ}$}$ .

5 0

3 years ago

Graph the inequality y > 3x + 3

natita [175]

Answer:

see below

Step-by-step explanation:

7 0

2 years ago

The endpoints of (MP)are M(2,1) and P(12,6). If point K partitions (MP) in a ratio of MK:KP = 3:2, what are the coordinates of K

GREYUIT [131]

Answer:

K(8, 4)

Step-by-step explanation:

Given:

M(2, 1), P(12, 6)

MK:KP = 3:2

Required:

Coordinates of K

SOLUTION:

Coordinates of K can be determined using the formula below:

$x = \frac{mx_2 + nx_1}{m + n}$

$y = \frac{my_2 + ny_1}{m + n}$

Where,

$M(2, 1) = (x_1, y_1)$

$P(12, 6) = (x_2, y_2)$

$m = 3, n = 2$

Plug in the necessary values to find the coordinates of K:

$x = \frac{mx_2 + nx_1}{m + n}$

$x = \frac{3(12) + 2(2)}{3 + 2}$

$x = \frac{36 + 4}{5}$

$x = \frac{40}{5}$

$x = 8$

$y = \frac{my_2 + ny_1}{m + n}$

$y = \frac{3(6) + 2(1)}{3 + 2}$

$y = \frac{18 + 2}{5}$

$y = \frac{20}{5}$

$y = 4$

The coordinates of K = (8, 4)

3 0

2 years ago