4 years ago

△DEF is rotated about point N to △D′E′F′ .

Mathematics

1 answer:

MatroZZZ [7]4 years ago

6 0

the answer is d the image is the same size

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Solve the simultaneous equations C^2+d^2=5 and 3c+4d=2

Naily [24]

If 3c+4d=2 then c=(2-4d)/3
And if you put that into the other equation
${\frac{2 - 4d}{3}}^{2} + {d}^{2} = 5$
Then you multiply everything by 3, getting

${(2 - 4d)}^{2} + 3 {d}^{2} = 15$
And then

$2 - 4d + \sqrt{3} d = \sqrt{15}$
Leaving
$d( \sqrt{3} - 4) = \sqrt{15} - 2$
I dont have a calc with me right now but you just pot this into the calculator:
$d = \frac{ \sqrt{15} - 2 }{ \sqrt{3} - 4}$
And when you get the number you insert it into the nest eqation to get c

$c = \frac{2 - 4d}{3}$
So basically

$c = \frac{2 - 4 \frac{ \sqrt{15} - 2}{ \sqrt{3} - 4} }{3}$

6 0

3 years ago

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What is 2/3 divided by 6/5

Vitek1552 [10]

That would be about 0.5555

3 0

4 years ago

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Please help need done fast!

gladu [14]

B 3 paper per min hope this helps