The area of the shaded region is 40π/3 square cm if the radius of the small circle r is 3 cm and the radius of the large circle R is 7 cm.
<h3>What is a circle?</h3>
It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle)
We have a circle in which the shaded region is shown.
The radius of the small circle r = 3 cm
The radius of the large circle R = 3+4 = 7 cm
The area of the shaded region:
= area of the large circle sector - an area of the small circle sector
= (120/360)[π7²] - (120/360)[π3²]
= 49π/3 - 3π
= 40π/3 square cm or
= 13.34π square cm
Thus, the area of the shaded region is 40π/3 square cm if the radius of the small circle r is 3 cm and the radius of the large circle R is 7 cm.
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The first system of equations has infinite solutions because you can write one equation as a linear combination of the other.The second system of equations has no solution because mathematically an incoherence results -14 = -2 / 7I attach the solutions for greater understanding.
x-4y=12; 5x-20y=60 --> infinitely many
y-7x=-14; 7y-49x=-2 --> none
Answer:
∠ B = 54°
Step-by-step explanation:
Supplementary angles sum to 180°.
Sum A and B and equate to 180, that is
7x + 14 + 5x - 26 = 180, that is
12x - 12 = 180 ( add 12 to both sides )
12x = 192 ( divide both sides by 12 )
x = 16
Thus
∠ B = 5x - 26 = 5(16) - 26 = 80 - 26 = 54°
In a triangle, the sum of the interior angles is 180.
So, you have
Plug the values for angles A and C:
1 minute = 60 seconds
You need to multiply the speed in m/s with 60 seconds and you will get the speed in meters/minute.
Covnersion factor is 60 seconds.
Solution would be : 20,1m/s * 60s = 1206meters/min
