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2 years ago

ASAP I NEED HELP I WILL GIVE BRAINLY:

Mathematics

1 answer:

Bogdan [553]2 years ago

8 0

Answer:

Short Answer is C.

Step-by-step explanation:

182 students out of 400 live off-campus, so 182 divided by 400 = .455 or 45.5%

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If p is a true statement and q is false, what is the truth value of p ∨ q? T F → T T F → F F T → T F T → F

stiks02 [169]

Answer:

If p is a true statement and q is false, what is the truth value of p ∨ q?

T F → T T F → F F T → T F T → F

Step-by-step explanation:

because it says P is true and q is false

4 0

2 years ago

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Solve (x + 3)2 + (x + 3) – 2 = 0. Let u = Rewrite the equation in terms of u. (u2 + 3) + u – 2 = 0 u2 + u – 2 = 0 (u2 + 9) + u –

Verdich [7]

Answer:

The solutions of the original equation are x=-5 and x=-2

Step-by-step explanation:

we have

$(x+3)^2+(x+3)-2=0$

Let

$u=(x+3)$

Rewrite the equation

$(u)^2+(u)-2=0$

Complete the square

$u^2+u=2$

$u^2+u+1/4=2+1/4$

$u^2+u+1/4=9/4$

rewrite as perfect squares

$(u+1/2)^2=9/4$

square root both sides

$(u+1/2)=\pm\frac{3}{2}$

$u=(-1/2)\pm\frac{3}{2}$

$u=(-1/2)+\frac{3}{2}=1$

$u=(-1/2)-\frac{3}{2}=-2$

the solutions are

u=-2,u=1

Alternative Method

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$(u)^2+(u)-2=0$

$a=1\\b=1\\c=-2$

substitute in the formula

$u=\frac{-1\pm\sqrt{1^{2}-4(1)(-2)}} {2(1)}$

$u=\frac{-1\pm\sqrt{9}} {2}$

$u=\frac{-1\pm3} {2}$

$u=\frac{-1+3} {2}=1$

$u=\frac{-1-3} {2}=-2$

the solutions are

u=-2,u=1

Find the solutions of the original equation

For u=-2

$-2=(x+3)$ ----> $x=-2-3=-5$

For u=1

$1=(x+3)$ ----> $x=1-3=-2$

therefore

The solutions of the original equation are

x=-5 and x=-2

4 0

2 years ago

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What is the average rate of change of the function over the interval x = 0 to x = 6?

Ymorist [56]

Answer:

15 2/3, or 47/3

Step-by-step explanation:

I'm going to assume, correctly or not, that you actually meant f(x) = 2x^2 - (1/3)x + 5. Double check on this right now, please.

If I'm right, then evaluate f(x) at x = 0 and x = 8:

f(0) = 5

and

f(8) = 2(8)^2 - (1/3)(8) + 5 = 128 - 8/3 + 5 = 133 - (2 2/3), or: 130 1/3

Then the average rate of change of f(x) = 2x^2 - (1/3)x + 5 over the interval [0,8] is:

130 1/3 - 5 125 1/3

a. r. c. = ------------------- = ---------------- = 15 2/3, or 47/3

8 - 0 8

6 0

2 years ago

Evaluate the equation. X=log27(3)

borishaifa [10]

From what i interpreted this question as... this is what i got and i hope i helped a bit

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2 years ago

Will give Brainliest! if right! Use the box-and-whisker plot find the range of the data.

k0ka [10]

Range = 100 - 50 = 50

answer is 50

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2 years ago

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