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Paha777 [63]
3 years ago
13

A 13.0 g piece of Styrofoam carries a net charge of â5.40 μC and floats above the center of a large horizontal sheet of plastic

that has a uniform charge density on its surface. What is the charge per unit area (in C/m2) on the plastic sheet?
Physics
1 answer:
kati45 [8]3 years ago
6 0

Answer:

σ =4.180×10^{-9} C/m^2

Explanation:

electric field due to non conducting sheet is

E=\frac{\sigma}{2\epsilon_0}

the force acting on the piece of Styrofoam

Eq= mg

⇒E= mg/q

now,

\frac{mg}{q} = \frac{\sigma}{2\epsilon_0}

⇒\sigma= \frac{2mg\epsilon_0}{q}

\sigma= \frac{2\times0.013\times9.81\times8.85\times10^{-12}}{5.40\times10^{-4}}

charge per unit area (in C/m2) on the plastic sheet σ =4.180×10^{-9} C/m^2

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A 12 volt battery in a motor vehicle is capable of supplying the starter motor with 150 A. It is noticed that the terminal volta
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Answer:0.0133 \Omega

Explanation:

Given

Voltage=12 V

Current(I)=150 A

V_{terminal}=10 V

r_{internal}=\frac{\Delta V}{I}

r_{internal}=\frac{12-10}{150}

r_{internal}=\frac{2}{150}=0.0133 \Omega

4 0
3 years ago
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9)A 64 kg parent and a 16 kg child meet at the center of an ice rink. They place their hands together and push. (A) Is the
Colt1911 [192]

Answer:

(A) <u>The same</u>

(B) <u>More</u>

(C) The magnitude of the parent's acceleration is 0.625 m/s²

Explanation:

The given parameters are;

The mass of the parent, m₁ = 64 kg

The mass of the child, m₂ = 16 kg

(A) By Newton's third law of motion, action and reaction are equal and opposite

Therefore, the action of the parent on the child is equal to the reaction of the child on the parent and vice versa

Therefore, the force experienced by the child is <u>the same</u> as the force experienced by the parent

(B) Newton's second law states that an objects acceleration is directly proportional to the applied force and inversely proportional to the mass of the object

Therefore, the parent and the child both experience the same force but the mass of the child is less than the mass of the parent and therefore, by Newton's second law, the acceleration of the child will be <u>more</u> than the acceleration of the parent for the same given force

(C) The acceleration of the child, a₂ = 2.5 m/s²

Let F₁ represent the force experienced by the parent, let F₂ represent the force experienced by the child and let a₁ represent the magnitude of the parent's acceleration

By Newton's third law, we have;

F₁ = F₂

Force, F = Mass, m × Acceleration, a

We can write, F = m × a

Therefore;

F₁ = m₁ × a₁ and F₂ = m₂ × a₂

∴ F₁ = F₂ gives;

m₁ × a₁ = m₂ × a₂

a₁ = (m₂ × a₂)/m₁ = (16 × 2.5)/64 = 0.625

∴ The magnitude of the parent's acceleration = a₁ = 0.625 m/s²

5 0
3 years ago
A hammer taps on the end of a 4.10-m-long metal bar at room temperature. A microphone at the other end of the bar picks up two p
xz_007 [3.2K]

Answer:

Speed of sound inside metal is ≅ 8200 \frac{m}{s}

Explanation:

Given :

Length of metal bar x = 4.10 m

From general velocity equation,

 v = \frac{x}{t}

Where v = speed of sound in air = 343 \frac{m}{s}

For finding time from above equation,

  t = \frac{x}{v}

 t = \frac{4}{343}

t = 0.01166 sec

Since pulses are separated by  t_{o} =  11.1 \times 10^{-3} = 0.0111 sec

So we take time difference,

\Delta t = t_{} -t_{o}  = 0.0005

So speed of sound in metal is,

 v = \frac{x}{\Delta t }

 v = \frac{4.10}{0.0005}

 v = 8200 \frac{m}{s}

4 0
3 years ago
HELP⚠️⚠️
alexgriva [62]

Answer:

I think u are traeling at speed of light and not ur friend

Explanation:

4 0
3 years ago
Read 2 more answers
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