Answer:
0.81452 atm
Explanation:
= Initial pressure = 1.43 L
= Volume
= Initial temperature = (28+273.15) K
= Final temperature = (-35+273.15) K
= Final pressure
From the ideal gas law we have
The pressure in the cylinder is 0.81452 atm
Answer:
<h2>
4.25m/s</h2><h2>
E. None of the option is correct</h2>
Explanation:
Using the law of conservation of momentum to solve the problem. According to the law, the sum of momentum of the bodies before collision is equal to the sum of the bodies after collision. The bodies move with the same velocity after collision.
Mathematically.
mu + MU = (m+M)v
m and M are the masses of the bullet and the block respectively
u and U are their respective velocities
v is their common velocity
from the question, the following parameters are given;
m = 20g = 0.02kg
u = 960m/s
M = 4.5kg
U =0m/s (block is at rest)
Substituting this values into the formula above to get v;
0.02(960)+4.5(0) = (0.02+4.5)v
19.2+0 = 4.52v
4.52v = 19.2
Dividing both sides by 4.52
4.52v/4.52 = 19.2/4.52
v = 4.25m/s
Since they have the same velocity after collision, then the speed of the block immediately after the collision is also 4.25m/s
They are all elevated land forms.
