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3 years ago

What does deposition mean in a sedimentary formation

1 answer:

4 0

Answer:

Sedimentary rocks are types of rock that are formed by the deposition and subsequent cementation of that material at the Earth's surface and within bodies of water. Deposition means that all the sediments, soil, and rocks are all compressed (tightly pressed into each other) and create sedimentary rocks.

I hope this helps! :)

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HELP PLZ!!!!!!!!!!!!!!

Sophie [7]

Answer:

Since binary is only 1 and 0, you can use a flashlight to display something similar to Morse code (see explanation below)

Explanation:

In binary, 1 means "on" and 0 means "off". A way you can use visible light is through turning on and off a flashlight. If the flashlight is turned on, it would represent a 1. If the flashlight is turned off, it would represent a 0. To make the message easier and more accurately understood for the receiver make sure to flash the lights in a consistent pattern (ex. each flash lasts no longer than half a second, one second between each digit, etc.)

For example, let's say you're trying to send the message "11001"

on on off off on

0 1 2 3 4 5 <em>Numbers represent seconds</em>

As you can see above the message starts at 0 seconds. Between 0 and 1 seconds the flashlight is turned on once. Between 1 and 2 seconds the flashlight is turned on again, Between 2 and 3 seconds as well as 3 and 4 seconds the flashlight is not turned on at all. And finally between 4 and 5 seconds the flashlight is turned on.

7 0

3 years ago

A 1.50 V potential difference is maintained across a 1.50 m wire that has a cross-sectional area of 0.600 mm2. How much power is

Goshia [24]

Given that the potential difference is V = 1.5 V.

The length of the wire is l = 1.5 m.

The cross-sectional area is

$\begin{gathered} A\text{ = 0.6 }mm^2 \\ =0.6\times10^{-6}m^2 \end{gathered}$

The resistivity of the wire is

$\rho\text{ = 5.25}\times10^{-8}\Omega\text{ m }$

We have to find the power dissipated in the wire.

First, we need to calculate resistance.

The resistance can be calculated as

$\begin{gathered} R\text{ = }\rho\frac{l}{A} \\ =5.25\times10^{-8}\times\frac{1.5}{0.6\times10^{-6}} \\ =0.13125\Omega \end{gathered}$

The formula to calculate power is

$P\text{ =}\frac{V^2}{R}$

Substituting the values, the power will be

$\begin{gathered} P\text{ = }\frac{(1.5)^2}{0.13125} \\ =17.1\text{ W} \end{gathered}$

Thus, the power dissipated in the wire is 17.1 W

5 0

2 years ago

Which statement is false?

podryga [215]

Answer:

D. Current with not flow through a wire if the magnet is outside the coil.

Explanation:

have a good day

5 0

3 years ago

The electrical loads in _____ circuits each have the same voltage drop, with equals the total applied voltage of the circuit.

Vesna [10]

Answer:

The electrical loads in parallel circuits each have the same voltage drop, with equals the total applied voltage of the circuit.

Explanation:

I did some research and the voltage drop across any branch of a parallel circuit is the same as the applied voltage.

3 0

2 years ago

At the very end of Wagner's series of operas The Ring of Nibelung, Brunnhilde takes the golden ring form the finger of the dead

Blababa [14]

Answer:

a) 404 m² b) apparent height = 7.5 m

Explanation:

This question is about refraction and total internal refraction.

Here I will take refractive index of air and water

$n_{air}=1\\ n_{water}=1.33=4/3$

Now let's look at the diagram I have attached here

At some angle A, the light from the ring (yellow point) under water will be totally internally refracted (B = 90°), which means that rays of light (yellow arrow) that make large enough angle A will not be able to escape from the water. Since we assumed that the ring is a point, there will be a critical cone of angle A with the ring at its apex which traces a circle of radius R on the surface of water, which, beyond this radius, no light could escape.

According to snell's law

$\frac{sin(B)}{sin(A)} = \frac{n_{water}}{n_{air}} = 4/3$

At critical angle B = 90°

$\frac{3)}{4}sin(B) = [tex]\frac{3}{4} sin(90^\circ ) = 0.75 = sin(A)$

Therefore

$A = 48.6^\circ$

With this, we can find the radius of the circle (refer to my diagram)

$h* tan (A) = R\\R =11.3 m$

And with that we can find the area

$A = \pi R^2=404\ m^2$

Additional Problem

For apparent depth from above, we can think that, since we are accustomed to seeing light at the speed of c in air, our brain interpret light from <em>any</em> source to be traveling at c. This causes light that originated under water, which has the speed of

$v_{water} = \frac{c}{n_{water}} = 0.75c$

to appear as if it has traveled with the same duration as light with speed c

In order for this to happen our brain perceive shortened length which is the apparent depth.

To put it in mathematical term

$t_{travel}=\frac{h_{apparent}}{v_{water}} =\frac{h}{c}$

So we get apparent depth

$h_{apparent}=0.75h = 7.5\ m$

4 0

3 years ago