-2y>12x-42
y<21-6x
so a is true
Answer:
ok so first we have to convert this into y intercept
4x-y=4
-4x
-y=-4x+4
*-1
y=4x-4
so the y intercept is -4
Hope This Helps!!!
<span>The integral of (x^2 + 6x)dx is 1/3x^3 + 3x^2 + c.
Because this is not an integration with specific bounds, you must include a constant at the end.
In general, to integrate, add 1 to the exponent of x and then whatever number is the exponent of x, divided the number in front of x by that.</span>
Answer:
Thanks
Step-by-step explanation:
We have to find midpoint M of the diagonal AC (or BD, there is no difference) so: