Where are the asymptotes for the following function located? f(x)= 7/ x^2-2x-24
2 answers:
Factor the demoniator:-
x^2 -2x - 24 = (x - 6)(x + 4)
the asymptotes occurs when denominator = 0
so here they are the vertical lines x = 6 and x = -4
Answer: Hence, the asymptotes of f(x) located at x=6 and x=-4.
Step-by-step explanation:
Since we have given that

We need to find the asymptotes for the above function:
Asymptotes occur when denominator becomes zero.

Hence, the asymptotes of f(x) located at x=6 and x=-4.
You might be interested in
Y = 2x - 3 . . . (1)
y = -2x + 5 . . . (2)
Equating (1) and (2),
2x - 3 = -2x + 5
2x + 2x = 5 + 3
4x = 8
x = 8/4 = 2
x = 2
y = 2(2) - 3 = 4 - 3 = 1
y = 1
Solution = (2, 1)
This is a right angle triangle.
So, by Pythagoras theorem,
√(32^2+20^2) = x
or √(1024+400) = x
or √1424 = x
or <em>37.74 = x</em>
Answer:
a: 4.12310563
b: 15.5563492
c: 17.8885438
Answer:
A.9
F.27
Step-by-step explanation:
how i got 9 is by counting by 9 and i count 27,and 54
additional 27 times 2= 54