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o-na [289]
3 years ago
10

Where are the asymptotes for the following function located? f(x)= 7/ x^2-2x-24

Mathematics
2 answers:
Zarrin [17]3 years ago
7 0
Factor the demoniator:-

x^2 -2x - 24 = (x - 6)(x + 4)

the asymptotes occurs when denominator = 0

so here they are  the vertical lines x = 6 and x = -4
m_a_m_a [10]3 years ago
5 0

Answer: Hence, the asymptotes of f(x) located at x=6 and x=-4.

Step-by-step explanation:

Since we have given that

f(x)= \frac{7}{x^2-2x-24}

We need to find the asymptotes for the above function:

Asymptotes occur when denominator becomes zero.

x^2-2x-24=0\\\\x^2-6x+4x-24=0\\\\x(x-6)+4(x-6)=0\\\\(x-6)(x+4)=0\\\\x=6,-4

Hence, the asymptotes of f(x) located at x=6 and x=-4.

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Change this equation, in standard form, to slope-intercept form: 2x + 3y = 18
Mandarinka [93]

Answer:

y = -2/3 + 18

Step-by-step explanation:

2x + 3y = 18       -----    here is the equation...

-2x          - 2x     -----    bring the 2x to the other side

3y = -2x + 18      -----    now you have to divide everything by 3 to get y by itself

y = -2/3 + 18       -----    Done!

6 0
2 years ago
Read 2 more answers
What is an equation of the line that passes through the point (-4,8) and is parallel to the line x+y=6? ​
satela [25.4K]

Answer:

y = -x + 4

Step-by-step explanation:

x + y = 6 => y = -x + 6

The line that parallel to y = -x + 6 has same slope so m = -1

Using coordinates (-4,8)

y = mx + b

8 = (-1)(-4) + b

8 = 4 + b

b = 4

then y = -x + 4

7 0
2 years ago
Ayala and sam were partners on a science project. Ayala spent 2 3/4 hours working on the project.Sam spent 1 3/4 on the project.
sergij07 [2.7K]

Answer:

  4 1/2 hours

Step-by-step explanation:

Total time worked was ...

  2 3/4 + 1 3/4 = (2 +1) + (3/4 +3/4)

  = 3 + (1 1/2) = 4 1/2 . . . hours

8 0
2 years ago
Consider the universal set R,R, define the interval A=[−7,1],A=[−7,1], interval B=(−1,5),B=(−1,5), and CC be the negative real n
AURORKA [14]
Draw a diagram representing the real number line, and the sets A  and B.

According to the diagram:

<span>1. A∪B= [-7, 5)

2. </span><span>2. A∩B∩C= (-1, 0)

</span>3. A∩(B∪C)= [-7, 1] <span>∩ (-INFINITY, 5) = [-7, 1]

4. </span>4. A^c ∪ B^c∪ C^c= (not A) ∪ (not B) ∪ (not C) = 

(-infinity, -7) ∪ (1, infinity)   ∪  (-infinity, -1] ∪ [5, infinity)   ∪ [0, infinity)

= (-infinity, -1] ∪ (1, infinity ) ∪ [0, infinity) = (-infinity, -1] ∪ [0, infinity) 

5. (C−A)∪(B−C)= "in C but not in A" union "in B but not in C"

=(-infinity, -7) ∪ [0, 5) 

8 0
3 years ago
Determine whether the given answer is a Solution or Not a Solution
zalisa [80]

Answer:

1- yes

2- yes

3- no

4- no

5- no

6- yes

Step-by-step explanation:

6 0
3 years ago
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