Answer:
4 dollars
Step-by-step explanation:
Unfortunately there isn't enough information.
Check out the diagram below. We have segment BC equal to 120 meters long. Points B, C, D and E are all on the edge of the same circle. According to the inscribed angle theorem, angles BDC and BEC are congruent. This shows that the surveyor could be at points D or E, or the surveyor could be anywhere on the circle. There are infinitely many locations for the surveyor to be at, which leads to infinitely many possible widths of this canal.
Answer:
0.0351478382 (To be precise)
Step-by-step explanation: Can I get brainliest? Thanks
1. Normal Distribution --> Z ~ (0,1^2)
2. Use normalcdf(lower bound, upper bound, μ, σ) function on a graphing calculator
P(Z≥103.53) = normalcdf(103.53, 1e99 [default], 80, 13)
P(Z≥103.53) ≈ 0.03
3. μ+σ ≈ 13.59% According to Z-distribution chart
80+13=93
So about 93 exceed only the top 16% (estimated answer not exact)
The length of the segment x is 16.2
Step-by-step explanation:
Here apply the Pythagorean relationship which states that the sum of squares of the sides is equal to the square of the hypotenuse.
Mathematically,
a²+b²=c²
where a=15, b=6, c=r
Hence;
15²+6²=c²
225+36=c²
√261=c
16.16
x⇒16.2
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Pythagorean relationship: brainly.com/question/11967357
Keyword: length, segment, nearest tenth
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Step-by-step explanation:
If (5) = 3
Then (10) = 6
Because 5 x 2 = 10 so 3 x 2 = 6