The change in potential energy of the proton is  5.6 x  Joule
 Joule
<h3>
What is a Uniform Electric Field ?</h3>
A uniform electric field is where the electric field strength is the same at all points in the field. In the uniform field, the force experienced by a charge is the same no matter where it is placed in the field.
Given that a proton moves a distance 10 cm in a uniform electric field of 3.5 kN C, in the direction of the field.
- The distance d = 10 cm = 0.1 m
- Electric field E = 3.5 KN/C
- Proton charge q = 1.6 x  C C
The Work done = Fd
but F = Eq
Recall that Electric field E = F/q = V/d
Where V = potential difference.
Let us first calculate the V
E = V/d
V = Ed
Substitute all the parameters into the formula above
V = 3.5 × 10³ × 0.1
V = 350 v
from F/q = V/d
make F the subject of formula and substitute it in work formula
F = Vq/d
W.D = Vq/d x d
W.D = Vq
Substitute all the parameters into the formula above
W.D = 350 x 1.6 x 
W.D = 5.6 x  J
 J
Work done = Energy = Potential Energy
Therefore, the change in potential energy of the proton is 5.6 x  <em> Joule</em>
<em> Joule</em>
<em />
Learn more about Electric Field here: brainly.com/question/14372859
#SPJ1
 
        
             
        
        
        
1st is sublimation 
2and is melting
3red is melting 
4th is sublimation 
sublimation is just "skipping" the liquid phase / state
 
        
             
        
        
        
You will use the height of the bridge from the ground. 
Solution:
Formula to be used is y=Viy(t)+g(t^2)/2 
Where:
Vi=initial velocity which is 0 m/s
 y=10 m
Gravitational acceleration or g =9.8m/s^2
T= time you need
Substitute all the given to the formula
10m=(0m/s)(t)+(9.8m/s^2)(t^2)/2
10mx2=9.8m/s^2(t^2)
Now isolate the variable you want to find which is T or time
10mx2/9.8m/s^2=t^2
20m/9.8m/s^2=t^2
Square root of 2.04= square root of t^2
T=1.43 secs
The answer is 1.43 seconds
 
        
                    
             
        
        
        
Answer:
Gravity
Explanation:
Thats the answer bucko. Gives the brainliest or I die
 
        
             
        
        
        
Answer:
Same direction: t=234s; d=6.175Km
Opposite direction: t=27.53s; d=0.73Km
Explanation:
If the automobile and the train are traveling in the same direction, then the automobile speed relative to the train will be  (<em>the train must see the car advancing at a lower speed</em>), where
 (<em>the train must see the car advancing at a lower speed</em>), where  is the speed of the automobile and
 is the speed of the automobile and  the speed of the train.
 the speed of the train.
So we have  .
.
So the train (<em>anyone in fact</em>) will watch the automobile trying to cover the lenght of the train L at that relative speed. The time required to do this will be:

And in that time the car would have traveled (<em>relative to the ground</em>):

If they are traveling in opposite directions, <u>we have to do all the same</u> but using  (<em>the train must see the car advancing at a faster speed</em>), so repeating the process:
 (<em>the train must see the car advancing at a faster speed</em>), so repeating the process:


