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Drupady [299]
3 years ago
6

A car is going 3 m/s, then it speeds up for 4 seconds. If it has an acceleration of 5m/s^2, find its final velocity. Which equat

ion can you use?
A Δx = vi*t + (½)at^2
B vf = vi + a*t
C Δx = (½)(vf + vi)*t
D vf^2 = vi^2 + 2aΔX
Physics
1 answer:
andreyandreev [35.5K]3 years ago
4 0

Well, since the question GIVES you the initial velocity, the acceleration, and the time, and ASKS for the final velocity, you'd be smart to find an equation that USES the initial velocity, the acceleration, and the time, and FINDS the final velocity.

Have a look at equation B ..... vf = vi + a*t . That's pretty durn close !

vf = (initial velocity) + (acceleration)*(time)

vf = (3 m/s) + (5 m/s²)*(4 sec)

vf = (3 m/s) + (20 m/s)

vf = 23 m/s

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Answer:

<em>When the speed is doubled, K = 100 J, when the speed is tripled, K = 225 J</em>

Explanation:

<u>Kinetic Energy </u>

Is the type of energy an object has due to its speed. It's proportional to the square of the speed.

The equation for the kinetic energy is:

\displaystyle K=\frac{1}{2}mv^2

Where:

m = mass of the object

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The kinetic energy is expressed in Joules (J)

The object has a kinetic energy of K=25 J when moving at v=5 m/s, thus the mass can be calculated by solving for m:

\displaystyle m=\frac{2K}{v^2}

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If the speed is doubled, v=10 m/s, the new kinetic energy is:

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If the speed is tripled, v=15 m/s, the new kinetic energy is:

\displaystyle K=\frac{1}{2}2\cdot 15^2

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