Answer:
Part a)
![T = 676.9 N](https://tex.z-dn.net/?f=T%20%3D%20676.9%20N)
Part b)
![T = 676.9 N](https://tex.z-dn.net/?f=T%20%3D%20676.9%20N)
Part c)
![T = 725.2 N](https://tex.z-dn.net/?f=T%20%3D%20725.2%20N)
Part d)
![T = 628.6 N](https://tex.z-dn.net/?f=T%20%3D%20628.6%20N)
Explanation:
Part a)
Since the gymnast is holding the rope and remains stationary
So total force is balanced on it
so we will have
T = mg
![T = (69)(9.81)](https://tex.z-dn.net/?f=T%20%3D%20%2869%29%289.81%29)
![T = 676.9 N](https://tex.z-dn.net/?f=T%20%3D%20676.9%20N)
Part b)
Now gymnast start climbing the rope at uniform speed
so here we have
![a = 0](https://tex.z-dn.net/?f=a%20%3D%200)
so again we will have same force equation
![T = mg](https://tex.z-dn.net/?f=T%20%3D%20mg)
![T = 676.9 N](https://tex.z-dn.net/?f=T%20%3D%20676.9%20N)
Part c)
Now gymnast start climbing up the rope at uniform acceleration
so now we will have
![T - mg = ma](https://tex.z-dn.net/?f=T%20-%20mg%20%3D%20ma)
![T = mg + ma](https://tex.z-dn.net/?f=T%20%3D%20mg%20%2B%20ma)
![T = 69(9.81 + 0.700)](https://tex.z-dn.net/?f=T%20%3D%2069%289.81%20%2B%200.700%29)
![T = 725.2 N](https://tex.z-dn.net/?f=T%20%3D%20725.2%20N)
Part d)
Now gymnast start sliding downwards with same uniform acceleration
so now we will have
![mg - T = ma](https://tex.z-dn.net/?f=mg%20-%20T%20%3D%20ma)
now we have
![mg - ma = T](https://tex.z-dn.net/?f=mg%20-%20ma%20%3D%20T)
![T = 69(9.81 - 0.7)](https://tex.z-dn.net/?f=T%20%3D%2069%289.81%20-%200.7%29)
![T = 628.6 N](https://tex.z-dn.net/?f=T%20%3D%20628.6%20N)
The point is the water table closest to the surface in valleys.
In areas of topographic relief, the water table generally follows the surface but tends to approach it in valleys and intersect the surface with streams and lakes. Closest to the surface is the vented zone where the interstices between the soil are filled with both air and water. Below this layer is a saturation zone where the gaps are filled with water.
The water table is the subsurface boundary between the soil surface and the area where groundwater saturates the space between sediment and rock fissures. At this boundary, water pressure equals atmospheric pressure. The top surface of the groundwater is the groundwater table. Beneath this surface, all pore spaces and cracks in sediments and rocks are completely filled and saturated with water. Groundwater occurs in these saturated layers known as saturation zones or water vapor zones.
Learn more about The water table here:-brainly.com/question/1362512
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3.
If the reaction forms a new substance it's a chemical reaction.
Answer:
Answer is 0
Explanation:
Given the information
First mass = m
Second mass = 3m
Initial velocity = v
Final velocity = v/3
The collision occuring here is inelastic and in inelastic collisions the kinetic energy is not conserved however the momentum is conserved.
According to conservation of momentum initial momentum is equal to final velocity.
Conservation of momentum is =
m1v1 + m2v2 = (m1 +m2)vf
Rearranging the equation to get final velocity we have =>
mv - 3mv/3 = 4mvf
vf = 0
Answer:
The car overtakes the truck at a distance d = 3266.2ft from the starting point
Explanation:
Problem Analysis
When car catches truck:
dc = dt = d
dc: car displacement
dt: truck displacement
tc = tt = t
tc: car time
tt : truck time
car kinematics :
car moves with uniformly accelerated movement:
d = vi*t + (1/2)a*t²
vi = 0 : initial speed
d = (1/2)*a*t² Equation (1)
Truck kinematics:
Truck moves with constant speed:
d = v*t Equation (2)
Data
We know that the acceleration of the car is 3.00 ft / s² and the speed of the truck is 70.0 ft / s .
Development problem
Since the distance traveled by the car is equal to the distance traveled by the truck and the time elapsed is the same for both, then we equate equations (1 ) and (2)
Equation (1) = Equation (2)
(1/2)*a*t² = v*t
(1/2)*3*t² = 70*t (We divide both sides by t)
1.5*t = 70
t = 70 ÷ 1.5
t = 46.66 s
We replace t = 46.66 s in equation (2) to calculate d:
d = 70*46.66 = 3266.2ft
d = 3266.2 ft