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kkurt [141]
3 years ago
10

What observations characterize solar maximum?

Physics
1 answer:
MakcuM [25]3 years ago
3 0
That maximum is the biggest thing..
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A 1.0-kilogram rubber ball traveling east at 4.0 meters per second hits a wall and bounces back toward the west at 2.0 meters pe
Mrrafil [7]

Answer:

8 J and 2 J

Explanation:

Given that,

Mass of the rubber ball, m = 1 kg

Initial speed of the rubber ball, u = 4 m/s (in east)

Final speed of the rubber ball, v = -2 m/s (in west)

We need to find the kinetic energy of the ball before it hits the wall, the kinetic energy of the ball after it bounces off the wall.

Initial kinetic energy,

K_i=\dfrac{1}{2}mv^2\\\\K_i=\dfrac{1}{2}\times 1\times (4)^2\\\\K_i=8\ J

Final kinetic energy,

K_f=\dfrac{1}{2}mv^2\\\\K_f=\dfrac{1}{2}\times 1\times (2)^2\\\\K_f=2\ J

So, the initial kinetic energy is 8 J and the final kinetic energy is 2 J.

8 0
3 years ago
What is the terminal velocity of a 6.00-kg mass object in falling with a drag force with a magnitude that depends on speed, v, a
3241004551 [841]

When object reached the terminal speed then its acceleration is zero

So as per Newton's II law we can say

F_{net} = 0

now in that case we can say that net force is zero so here weight of the object is counter balanced by the drag force when it will reach at terminal speed

so we can write

mg - F_d = 0

so here we are given that

F_d = 30

6*9.8 - 30*v = 0

58.8 - 30 *v = 0

v = \frac{58.8}{30}

v = 1.96 m/s

so terminal speed will be nearly 2 m/s

6 0
3 years ago
Which list shows the development of atomic models in chronological order?
ikadub [295]
I think it would be plum pudding, solid ball, solar system.
8 0
3 years ago
A lump of clay whose rest mass is 4 kg is travelling at three-fifths the speed of light when it collides head-on with an identic
Harman [31]

Answer:

mass of the composite lump is 10 kg

Explanation:

given data

mass = 4 kg

to find out

mass of composite lump

solution

we know energy is conserved so

so m1 = m2 = m0 that is 4kg

and

E(1) release+ E(2) release = E(1,2) rest

so γ(1)m(1)c² + γ(2)m(2)c²  = Mc²    ..........................1

that why here

|v(1)| = |v(2)| = 3/5 c        ......................2

and

γ = 1 / √(1 − v²/c²)           .......................3

put here v = 3 and c is 5

γ = 1 /√(1 − 9/25)

γ =  5/4

so

γ(1) = γ(2) = γ = 5/4  

so from equation 1

γ(1)m(1)c² + γ(2)m(2)c²  = Mc²

M = 2γm0

M = 2(5/4 )(4)

M = 10 kg

so mass of the composite lump is 10 kg

7 0
4 years ago
Some of the principal minerals commonly found in igneous rocks are
Verdich [7]
I believe that the answer is C. Hope this Helps:)))
3 0
3 years ago
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