Answer:
Force exerted, F = 1.5 N
Explanation:
It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.
i.e. u = 0
v = 30 m/s
Time taken, t = 0.06 s
Mass of the paper, m = 0.003 kg
We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :
F = 1.5 N
So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.
Explanation:
It is given that,
Force applied to object, 
Position, 
(b) The cross product of force and position vector is used to find the net torque about the z axis. It is given by :
or
The torque is acting in -z axis.
(a) The magnitude of torque is given by :
Hence, this is the required solution.
1. they all come from the clouds 2.they are all formed by precipatation. hope this helps enjoyyyyyy!!!!!!!!!!!!!
Answer:
Explained
Explanation:
public int dimension(int [][]a2d,int nElements)
{
int count = 0;
for(int i = 0;i < a2d.length ; i++)
{
count = count + a2d[i].length;
}
return count;
}
Well we know it has to be greater than 300,000 km/s since we can't see it.
We can't calculate it any closer than that using the given information.
