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STatiana [176]
3 years ago
11

balls a, with a mass of 20 kg, is moving to the right at 20 m/s. At what velocity should Ball B, with a mass of 40 kg, move so t

hat they both come to standstill upon collision?
Physics
1 answer:
Leya [2.2K]3 years ago
3 0
In that case, their momentum must be equal. 
So, m1v1 = m2v2
20 * 20 = 40 * v2
v2 = 400 / 40
v2 = 10

In short, Your Answer would be: 10 m/s

Hope this helps!
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Answer:

1. A substance that can be separated into two or more substances only by a chemical change is a(n) _____.

solution

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2.

Which of the following materials is a substance?

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3.

The first figure in a properly written chemical symbol always is _____.

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Explanation:

5 0
2 years ago
The force required to compress a non-standard spring as a function of displacement from equilibrium x is given by the equation F
UNO [17]

Answer:

The equation which define the work done by spring is w = 45 x³ - 8 x²

Explanation:

Given as :

The force is the function of distance x

I.e F(x) = a x² - b x

where

a = 45 N/m²

b = 8 N/m

Now, Wok done = Force ×displacement

I.e W = F . ds

So , W = (a x² - b x) × x

or, W = (45 x² - 8 x) × x

Or, w = 45 x³ - 8 x²

So, the equation which define the work done by spring is w = 45 x³ - 8 x²

Hence The equation which define the work done by spring is w = 45 x³ - 8 x²  Answer

7 0
3 years ago
A train rolls to a stop along a horizontal track without the conductor applying the brakes. What answer choice BEST explains why
Naya [18.7K]

Answer:

B

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Friction always eventually stops whatever is in motion.

4 0
4 years ago
The nucleus of 8be, which consists of 4 protons and 4 neutrons, is very unstable and spontaneously breaks into two alpha particl
Mama L [17]

The acceleration of the charge is 1.07 × 10²⁸ m/s². It is obtained as the force per unit mass of the charge.

<h3>What is Columb's law?</h3>

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The electric force is found as;

\rm F = \frac{Kq_1q_2}{r^2} \\\\ F= \frac{9 \times 10^9 \times( 3.2 \times 10^{-19})^2}{(3.60 \times 10^{-15})^2}\\\\ F=71.1 \ N

The acceleration of the charge is found as;

\rm a = \frac{F}{m} \\\\ \rm a = \frac{71.1}{4.0026 \TIMES 1.66 \TIMES 10^{-27}} \\\\ a=1.07 \times 10^{28} \ m/s^2

Hence,the acceleration of the charge is 1.07 × 10²⁸ m/s².

To learn more about Columb's law, refer to the link;

brainly.com/question/1616890

#SPJ4

3 0
2 years ago
A student throws a 0.22 kg rock horizontally at 20.0 m/s from 10.0 m above the ground. Find the initial kinetic energy of the ro
LekaFEV [45]

Answer:

44J

Explanation:

Given parameters:

Mass of rock  = 0.22kg

Initial velocity  = 20m/s

Distance moved  = 10m

Unknown:

Initial kinetic energy of the rock  = ?

Solution:

To solve this problem, we need to understand that kinetic energy is the energy due to the motion of a body.

It is mathematically expressed as;

     Kinetic energy  = \frac{1}{2} m v²

m is the mass

v is the velocity

   Kinetic energy  =  \frac{1}{2} x 0.22 x 20²   = 44J

6 0
3 years ago
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