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riadik2000 [5.3K]
3 years ago
12

The mass of all bicycles and riders indicated in the graph are equal. What indicates the order of their average velocity from gr

eatest to least?
Physics
2 answers:
Amanda [17]3 years ago
8 0

Answer: A

Explanation: I took the test

antoniya [11.8K]3 years ago
5 0

the answer is  A) A, D, C, B

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What is the electric field strength just outside the flat surface of the conductor?
inna [77]
We can find the answer step-by-step:

1) The electric charges on a conductor must lie entirely on its surface. This is because the charges have same sign, so the force acting between each other is repulsive therefore the charges must be as far apart as possible, i.e. on the surface of the conductor.

2) We consider a cylinder perpendicular to the surface of the conductor, that crosses the surface with its section. We then apply Gauss law, which states that the flux of the electric field through this cylinder is equal to the total charge inside it divided the electrical permittivity:
\Phi =  \frac{Q}{\epsilon_0}

3) The electric field outside the surface is perpendicular to the surface itself (otherwise there would be a component of the electric force parallel to the surface, which would move the charge, violating the condition of equilibrium). The electric field inside the conductor is instead zero, because otherwise charges would move violating again equilibrium condition. Therefore, the only flux is the one crossing the section A of the cylinder outside the surface: 
\Phi = E A

4) The total charge contained in the cylinder is the product between the section, A, and the charge density \sigma on the surface of the conductor:
Q=\sigma A

5) Substituting the flux and the charge density inside Gauss law, we can find the electric field just outside the surface of the conductor:
EA= \frac{\sigma A}{\epsilon_0}
therefore
E= \frac{\sigma}{\epsilon_0}
4 0
3 years ago
I am boring and you can talk to me?
sladkih [1.3K]
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4 0
3 years ago
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A uniform solid ball with a mass , M, is placed at the top of an inclined plane and released. What will be the velocity of the b
eimsori [14]

Answer:v=\sqrt{\frac{10}{7}\cdot gH}

Explanation:

Given

Mass of ball is M

Height of incline is H

Here conservation of energy will provide the velocity at bottom

Energy at top of incline plane =MgH

Energy at bottom=Kinetic energy+Rotational energy

Assuming Pure rolling we can write

v=\omega R

where v=velocity of ball

\omega=angular velocity of ball

R=radius of ball

E_b=\frac{1}{2}Mv^2+\frac{1}{2}I\omega ^2

where I=moment of inertia of ball

I=\frac{2}{5}MR^2

E_b=\frac{1}{2}Mv^2+\frac{1}{2}\times \frac{2}{5}MR^2\times (\frac{V}{R})^2

E_b=\frac{7}{10}Mv^2

Now ,

MgH=\frac{7}{10}Mv^2

v=\sqrt{\frac{10}{7}\cdot gH}

8 0
3 years ago
An electromagnetic wave with frequency 65.0Hz travels in an insulating magnetic material that has dielectric constant 3.64 and r
lakkis [162]

Answer:

  The wavelength of the wave is 1.06\times10^6 m  

Explanation:

Lets calculate

We know an electromagnetic wave is propagating through an insulating magnetic material of dielectric constant K and relative permeability K_m ,then the speed of the wave in this dielectric medium is \nu is less than the speed of the light c and is given by a relation

               \nu=\frac{c}{\sqrt{KK_m} }  --------- 1

In case the electromagnetic  wave propagating through the insulating magnetic material , the amplitudes of electric and  magnetic fields are related as -

             E_m_a_x= \nu B_m_a_x

The magnitude of the 'time averaged value' of the pointing vector is called the intensity of the wave and is given by a relation

                       I = S_a_v

                        \frac{E_m_a_xB_m_a_x}{2K_m\mu0}----------- 3

now , we will find the speed of the propagation of an electromagnetic wave by using equation 1

\nu=\frac{c}{\sqrt{KK_m} }

Putting the values ,

   =\nu= \frac{3.00\times10^8}{\sqrt{(3.64)(5.18)} }

 =0.6908\times10^8m/s

 = 6.91\times10^7m/s

Now , using this above solution , we will find the wavelength of the wave -

     \lambda=\frac{\nu}{f}

    Putting the values from above equations -

  \frac{6.91\times10^7m/s}{65.0Hz}

        \lambda= 1.06\times10^6 m

Hence , the answer is \lambda= 1.06\times10^6 m

8 0
3 years ago
No if radiactive plutonium is burnt in the air it produces plutonium oxide.do we expect the oxide to be radiactive
DerKrebs [107]

Answer:

A naturally radioactive element of the actinide metals series. Plutonium is used as a nuclear fuel, to produce radioisotopes for research, Plutonium dioxide is formed when plutonium or its compounds (except the phosphates) are ignited in air, and  Plutonium oxide fired at temperatures 600 C is difficult to rapidly.

Explanation:

3 0
3 years ago
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