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3 years ago

EXPLAIN the measures that can be taken to ensure safety in a storm.

Physics

1 answer:

ICE Princess25 [194]3 years ago

6 0

Hello There!

Great Question You Asked.

I Will Provide A Number Of Steps To Below To Show You Measures of Being Safe

Number 1.

Find shelter immediately. If you find yourself caught in a lightning storm, the key to minimizing danger is to get inside a protective structure. While most people seek shelter if lightning appears to be near, people commonly wait too long to seek shelter. If you can detect lightning, it may be close enough to strike you so always make sure you are safe.

Number 2.

Try to stay away from windows because windows provide a direct path for lightning.

Number 3.

Don’t touch anything metal or electrical.

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Question 1 (1 point)

MatroZZZ [7]

Answer:

The work done by the frictional force is 600J.

Explanation:

The work $W$ done by the frictional force is

$W= Fd$ .

Now, $F = 60N$ and $d =10m$ ; therefore,

$W= (60N)(10m)$

$\boxed{W = 600J.}$

Hence, the work done by friction is 660J.

7 0

3 years ago

What is the value of 9682 when rounded to three significant figures

sdas [7]

9700 because 682 rounds to 700

5 0

3 years ago

1. My grass is dying, and I believe it's because it is not getting enough water. Sol

trasher [3.6K]

Answer: I actually need the same answer

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5 0

3 years ago

A resistor with an unknown resistance is connected in parallel to a 13 Ω resistor. When both resistors are connected in parallel

larisa86 [58]

Answer:

R2 = 10.31Ω

Explanation:

For two resistors in parallel you have that the equivalent resistance is:

$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\\$ (1)

R1 = 13 Ω

R2 = ?

The equivalent resistance of the circuit can also be calculated by using the Ohm's law:

$I=\frac{V}{R_{eq}}\\\\R_{eq}=\frac{V}{I}$ (2)

V: emf source voltage = 23 V

I: current = 4 A

You calculate the Req by using the equation (2):

$R_{eq}=\frac{23V}{4A}=5.75\Omega$

Now, you can calculate the unknown resistor R2 by using the equation (1):

$\frac{1}{R_2}=\frac{1}{R_{eq}}-\frac{1}{R_1}\\\\R_2=\frac{R_{eq}R_1}{R_1-R_{eq}}\\\\R_2=\frac{(5.75\Omega)(13\Omega)}{13\Omega-5.75\Omega}=10.31\Omega$

hence, the resistance of the unknown resistor is 10.31Ω

8 0

3 years ago

Read 2 more answers

A person slaps her leg with her hand, which results in her hand coming to rest in a time interval of 2.75 ms2.75 ms from an init

kumpel [21]

Answer:

2677.3 N

Explanation:

v₀ = initial speed of the hand = 4.75 m/s

v = final speed of the hand = 0 m/s

m = Total mass of hand and forearm = 1.55 kg

t = time interval for hand to come to rest = 2.75 ms = 0.00275 s

F = Force applied on the leg

Using Impulse-change in momentum equation

F t = m (v - v₀)

F (0.00275) = (1.55) (0 - 4.75)

F = - 2677.3 N

magnitude of force = 2677.3 N

6 0

3 years ago