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grandymaker [24]
3 years ago
15

EXPLAIN the measures that can be taken to ensure safety in a storm.

Physics
1 answer:
ICE Princess25 [194]3 years ago
6 0

Hello There!

Great Question You Asked.

I Will Provide A Number Of Steps To Below To Show You Measures of Being Safe

Number 1.

Find shelter immediately. If you find yourself caught in a lightning storm, the key to minimizing danger is to get inside a protective structure. While most people seek shelter if lightning appears to be near, people commonly wait too long to seek shelter. If you can detect lightning, it may be close enough to strike you so always make sure you are safe.

Number 2.

Try to stay away from windows because windows provide a direct path for lightning.

Number 3.

Don’t touch anything metal or electrical.

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I attach a 4.1 kg block to a spring that obeys Hooke's law and supply 3.8 J of energy to stretch the spring. I release the block
borishaifa [10]

Answer:

The amplitude of the oscillation is 2.82 cm

Explanation:

Given;

mass of attached block, m = 4.1 kg

energy of the stretched spring, E = 3.8 J

period of oscillation, T = 0.13 s

First, determine the spring constant, k;

T = 2\pi \sqrt{\frac{m}{k} }

where;

T is the period oscillation

m is mass of the spring

k is the spring constant

T = 2\pi \sqrt{\frac{m}{k} } \\\\k = \frac{m*4\pi ^2}{T^2} \\\\k = \frac{4.1*4*(3.142^2)}{(0.13^2)} \\\\k = 9580.088 \ N/m\\\\

Now, determine the amplitude of oscillation, A;

E = \frac{1}{2} kA^2

where;

E is the energy of the spring

k is the spring constant

A is the amplitude of the oscillation

E = \frac{1}{2} kA^2\\\\2E = kA^2\\\\A^2 = \frac{2E}{k} \\\\A = \sqrt{\frac{2E}{k} } \\\\A =  \sqrt{\frac{2*3.8}{9580.088} }\\\\A = 0.0282 \ m\\\\A = 2.82 \ cm

Therefore, the amplitude of the oscillation is 2.82 cm

8 0
3 years ago
A rock layer that stores and transmits water​
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Answer

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