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Lyrx [107]
2 years ago
8

Can someone help me ASAP

Physics
1 answer:
Phantasy [73]2 years ago
7 0

Well I don't know.  Let's actually LOOK at the picture and see if that helps.

A,  B,  C,  and D all have the same TOTAL length, but  A  has the most waves crammed into that same total length.

By golly, that means the length of <u><em>each</em></u> wave in  A  must be shorter than each wave in  B,  C,  or D.

The correct choice is <em> A </em>.  Looking at the picture did the trick !

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A 5-g lead bullet traveling in 20°C air at 300 m/s strikes a flat steel plate and stops.
densk [106]

To solve this problem it is necessary to apply the concepts related to the Kinetic Energy and the Energy Produced by the heat loss. In mathematical terms kinetic energy can be described as:

KE = \frac{1}{2} mv^2

Where,

m = Mass

v = Velocity

Replacing we have that the Total Kinetic Energy is

KE = \frac{1}{2} mv^2

KE = \frac{1}{2} (5*10^{-3})(300)^2

KE =  225J

On the other hand the required Energy to heat up t melting point is

Q_1 = mC_p \Delta T

Q_2 = L_f m

Where,

m = Mass

C_p =Specific Heat

\Delta T =Change at temperature

L_f = Latent heat of fussion

Heat required to heat up to melting point,

Q = Q_1+Q_2

Q = mC_p \Delta T+L_f m

Q = 5*0.128*(327-20) + 5*24.7

Q = 310J

The energy required to melt is larger than the kinetic energy. Therefore the heat of fusion of lead would be 327 ° C: The melting point of lead.

4 0
3 years ago
A drag racer starts from the rest and accelerates at 7.4m/s^2.how far will he travel in 2.0 seconds?
Vesna [10]

Answer:

14.8 m

Explanation:

S= ut + \frac{1}{2}at^{2}

where u = initial velocity

S= (0 \frac{m}{s})(2s) + \frac{1}{2}(7.4\frac{m}{s^{2} })(2s^{2})

S=  \frac{1}{2}(7.4\frac{m}{s^{2} })(2s^{2})

S=14.8 m

8 0
3 years ago
A student wants to design an experiment to study the transformation of mechanical energy. Which object can be used to investigat
Vsevolod [243]
I guess it’s the 3rd one
7 0
2 years ago
Read 2 more answers
To test the quality of a tennis ball, you drop it onto a floor from a height of 4.00m . It rebounds to a height of 2.00 m. If th
Agata [3.3K]
In this problem, we apply the equation regarding  kinematics  expressed as  vf^2 = v0^2 + 2as  vf eventually becomes zero because the ball stops in the end. a = -9.8 m/s2s = 2 metres this time 
This gives initial velocity, vo equal to 6.26m/s 
now 6.26-(-8.85) = 15.11m/s 

change in velocity/change in time = average acceleration 15.11/(12/1000) = 1259.167 m/s^2
3 0
2 years ago
Read 2 more answers
What is the vertical acceleration of a paper airplane that is launched horizontally with an initial velocity of 2.3 m/s?
mr_godi [17]

Answer:

<em>The vertical acceleration is -9.81 m/s^2</em>

Explanation:

When a body is projected, the body experiences an acceleration in the vertical axis that is proportional to the acceleration due to gravity of the earth, which is equal to 9.81 m/s^2. In this case, the acceleration acts to stop the vertical motion of the paper plane, and hence is a deceleration, which explains the negative vertical acceleration.

8 0
3 years ago
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