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3 years ago

A force of 6.0 N gives a 2.0 kg block an acceleration of 3.0

Physics

1 answer:

Semenov [28]3 years ago

7 0

Explanation:

The Net Force of the object can be written by:

Fnet = ma

where m is the mass of the object in kg

a is the acceleration of the object in m/s^2

Hence by applying the formula we get:

Fnet = (2.0)(3.0)

= 6N

We also know that Net force is also the sum of all forces acting on an object. In this case Friction and the Pushing Force is acting on the object. Hence we can write that:

Fnet = Pushing Force + (-Friction)

6N = 6N - Friction

Friction = 0N

Hence the force of friction is 0N.

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Which planet in the list below is larger than Earth? A. Saturn B. Mars C. Mercury D. Venus

Alborosie

ANSWER:

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3 years ago

Read 2 more answers

A cylinder is fitted with a piston, beneath which is a spring, as in the drawing. The cylinder is open to the air at the top. Fr

astraxan [27]

Answer:

x = 0.0734 m = 7.34 cm

Explanation:

First we shall calculate the area of the piston:

$Area = \pi radius^2\\Area = \pi (0.028\ m)^2\\Area = 0.00246\ m^2$

Now, we will calculate the force on the piston due to atmospheric pressure:

$Atmospheric\ Pressure = \frac{Force}{Area}\\\\Force = (Atmospheric\ Pressure)(Area)\\Force = (101325\ N/m^2)(0.00246\ m^2) \\Force = F = 249.56\ N$

Now, for the compression of the spring we will use Hooke's Law as follows:

$F = kx\\$

where,

k = spring constant = 3400 N/m

x = compression = ?

Therefore,

x = 0.0734 m = 7.34 cm

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3 years ago

A thin spherical glass shell in air is filled with an unknown liquid. A horizontal parallel light beam is incident on the shell

sammy [17]

I have the exact same question, any chance you figured it out since you posted this?

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3 years ago

Two persons manage to push a motorcar of mass 1200 kg at uniform velocity along a level road, The same motorcar can be pushed by

densk [106]

Answer:

40N by each person.

Explanation:

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3 years ago

How much work is done by a 120N force applied to a box that moves 5m?

Vsevolod [243]

Answer:

600 Joules

Explanation:

Using the formula F*d*cosФ. Assuming the Ф is parallel to the motion. The work done is 600 Joules.

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3 years ago