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3 years ago

Use the component form of newton's second law to write an expression for the x component of the net force, σfx

1 answer:

8 0

Draw a free body diagram to show which forces act in the x and y directions. The x component equation is σfx = 0. The σfx being all the forces acting in the x direction.

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Explain the difference between si base units and derived units. give an example of each

34kurt

Base SI unit is the unit that used for simple quantity like time=second and length= meter. They only have one unit.
Derived unit is more complex because you multiply or divide at least two base SI, making it have more than 1 unit. The example could be velocity which was time/length = m/s

6 0

4 years ago

Bob is pushing a box across the floor at a constant speed of 1.5 m/s, applying a horizontal force whose magnitude is 60 n. alice

earnstyle [38]

120n

since the speed is doubled, her force is doubled

7 0

4 years ago

Calculate the force exerted by a mental ball having a mass of 70kg moving with speed of 20m/s>2

lord [1]

Answer:

F = 1400 N

Explanation:

It is given that,

Mass of the ball, m = 70 kg

It is moving with an acceleration of 20 m/s². We need to find the force exerted by the ball.

Force is given by the product of mass and acceleration. So,

F = ma

$F=70\ kg\times \ 20m/s^2\\\\F=1400\ N$

So, the force of 1400 N is exerted by a metal ball.

8 0

3 years ago

A 35-year-old patent clerk needs glasses of 50-cm focal length to read patent applications that he holds 25 cm from his eyes. Fi

Natali5045456 [20]

Answer:

28.57 cm

Explanation:

We are given that

Focal length, $f=50 cm$

Distance of application from his eyes,s=40 cm

$\frac{1}{s}+\frac{1}{s'}=\frac{1}{f}$

$\frac{1}{40}+\frac{1}{s'}=\frac{1}{50}$

$\frac{1}{s'}=\frac{1}{50}-\frac{1}{40}=\frac{4-5}{200}$

$s'=\frac{200}{-1}=-200 cm$

s=25 cm

Substitute the values

$\frac{1}{25}-\frac{1}{200}=\frac{1}{f'}$

$\frac{8-1}{200}=\frac{1}{f'}$

$\frac{1}{f'}=\frac{7}{200}$

$f'=\frac{200}{7}=28.57 cm$

6 0

3 years ago

A dart gun shoots a dart with an angle of 45' above horizontal During the upward part of the trajectory the gravitational accele

ludmilkaskok [199]

Answer:

4. Downward and its value is constant

Explanation:

As this is a case of projectile motion, we use the reference frame where upward direction to be positive for $y$ , and in the same way to be negative in the downward direction. On another hand, we have that gravity is always acting this means that gravitational acceleration g is directed downward constantly over the dart not only during the upward but also during the downward part of the trajectory. And it is ruled by the following equations.