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Alona [7]
3 years ago
9

Philosophy: The Big Picture Unit 8

Physics
1 answer:
SVEN [57.7K]3 years ago
5 0

D. Pragmatism applies to everyone, but utilitarianism is concerned with the upper class.
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If two items are equal in size, the denser one will
Talja [164]
Be heavier

density=mass÷volume

if two items have the same size they have the same volume so the heavier one will be the denser one
6 0
4 years ago
What is the velocity of a 2000 kg truck with a momentum of 48,000 kg•m/s?
Goshia [24]

Answer:

24

Explanation:

momentum= mass* velocity

velocity= momentum/ mass

5 0
3 years ago
Help ASAP PLEASE.............:3​
Evgesh-ka [11]

Answer:

temperature measures heat - the unit is Celsius - and it is measured with a thermometer.

length is measuring how long, tall, or wide something is  - the base unit it metres - and it is measured with a ruler or a metre stick

volume is measuring the quantity of a three dimensional space - the unit is cubic centimetre - you find volume by taking the measurements with a ruler

mass is measuring how much space something takes up/ weight - unit is the gram - you use a scale

8 0
3 years ago
Water enters a typical garden hose of diameter 0.016 m with a velocity of 3 m/s. Calculate the exit velocity of water from the g
Vladimir79 [104]

Answer:

v₂ = 306.12 m/s

Explanation:

We know that the volume flow rate of the water or any in-compressible liquid remains constant throughout motion. Therefore, from continuity equation, we know that:

A₁v₁ = A₂v₂

where,

A₁ = Area of entrance pipe = πd₁²/4 = π(0.016 m)²/4 = 0.0002 m²

v₁ = entrance velocity = 3 m/s

A₂ = Area of nozzle = πd₂²/4 = π(0.005 m)²/4 = 0.0000196 m²

v₂ = exit velocity = ?

Therefore,

(0.0002 m²)(3 m/s) = (0.0000196 m²)v₂

v₂ = (0.006 m³/s)/(0.0000196 m²)

<u>v₂ = 306.12 m/s</u>

5 0
3 years ago
A piston/cylinder contains 2 kg of water at 20◦C with a volume of 0.1 m3. By mistake someone locks the piston, preventing it fro
morpeh [17]

Answer:

Hi

Final temperature = 250.11 °C

Final volume = 0,1 m3.

Process work = 0

Explanation:

The specific volume in the initial state is: v = 0.1m3/2 kg = 0.05 m3/kg.

This volume is located between the volumes as saturated liquid and saturated steam at 20 °C. For this reason the water is initially in a liquid vapor mixture. As the piston was blocked the volume remains constant and the process is isometric, also known as isocoric process, so the final temperature will be the water temperature at a saturated steam of v=0.05m3/kg, which is obtained by using steam tables for water, by linear interpolation. As follows, using table A-4 of the Cengel book 7th Edition:

v=0.05 m3/kg

v1=0.057061 m3/kg

T1=242.56°C

v2=0.049779 m3/kg

T2=250.35°C

T=\frac{T2-T1}{v2-v1} x(v-v1)+T1=\frac{250.35°C-242.56°C}{0.049779m3/kg-0.057061m3/kg}x(0.05m3/kg-0.057061m3/kg)+242.56°C=250.11°C

The process work is zero because there is no change in volume during heating:

W=PxΔv=Px0=0

where

W=process work

P=pressure

Δv=change of volume, is zero because the piston was blocked so the volume remains constant.

7 0
3 years ago
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