Can anyone help me out? Find a and b
1 answer:
If you look at your graph you see that there is a hole at x = 3. This results from a removeable discontinuity. That means that when we factor the numerator to (x-3)(x-1), that (x-3) cancels out between the numerator and denominator and a hole is what results from that cancelation. The other factor for the denominator is found where the vertical asymptote of the function is, which is found at x = -4. That means that the 2 factors for the denomonator are (x-3) and (x+4). When you FOIL those out, you get . That means that a = 1 and b = -12
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Observe the graph below. This graph represents the scenario.
The question is ill formated, the complete question is
In a simulation, a moving object accelerates from rest to 4 meters per second in 2 seconds. For the following three seconds, it increases linearly until it reaches a speed of 10 meters per second. Following three seconds at that speed (acceleration = 0), the item progressively decelerates until it comes to rest two seconds later. Draw the graph of this scenario for 10 seconds?
I'll describe how the graph may show.
It will move diagonally upward from time 0 to 2 seconds until it reaches the y axis at a speed of 4 m/s.
Then, from 2 to 5, the position will move up diagonally until it reaches the y axis at a speed of 10 m/s.
The next 5 to 8 seconds will be horizontal.
After that, it will descend diagonally.
Observe the graph below. This graph represents the scenario.
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