Answer:
1) thiamine pyrophosphate -activation of aldehydes
2) coenzyme A -acyl group transfer
3) biotin -CO2 activation/transfer
4) NAD -oxidation/reduction
Explanation:
1. Thiamine pyrophosphate: This is a derivative of Vitamin B1 also known as thiamine. It contains a pyrimidine group linked to the thiazole ring. This connection is further linked to the pyrophosphate group. It functions as a coenzyme in all reactions involving alpha-keto acids. This produces activated aldehydes that could be subject to oxidation.
2. Coenzyme A: This cofactor is a thiol that reacts with carboxylic acids to form thioesters. In so doing, it carries the acyl group. In this condition, it can also be referred to as acyl CoA.
3. Biotin: Also known as Vitamin B7, biotin consists of an ureido ring merged with tetrahydrothiophene. The ureido ring contains the CO2 that can be transferred or activated. Five carboxylase enzymes use biotin as a cofactor in processes such as fat synthesis, glucose generation and the breakdown of sugar.
4. NAD: Nicotinamide adenine dinucleotide consists of two dinucleotides connected to each other at their phosphate groups. NAD exists in two states which are the NAD+ and NADH states. These two states serve as oxidizing and reducing agents respectively. The oxidizing agent becomes reduced to NADH after accepting electrons from other compounds. NADH donates an electron and becomes oxidized to NAD+.
Answer:
Yep, this is my new pick up line
Explanation:
Answer:
90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love you
Explanation:
Answer:
Heat is released.
Explanation:
Exothermic reactions are reactions that give off radiant heat when you come in close contact with them.
Answer:
Explanation:
<u>1) Data:</u>
a) n = ?
b) V = 50.0 dm³ = 50.0 liter
c) p = 100.0 kPa
d) T = 50 °C
<u>2) Physical law:</u>
<u>3) Constants:</u>
- R = 0.08206 atm-liter / K-mol
<u>4) Unit conversions:</u>
- T = 50 + 273.15 K = 323.15 K
- P = 100.0 kPa × (1 amt /101,325 kPa) = 0.9869 atm
<u>5) Solution:</u>
- n = 0.9869 atm × 50.0 liter / (0.08206 atm-liter /K-mol × 323.15 K)
