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stepladder [879]
3 years ago
7

PLEASE HELP ASAAAAPPPPPPP

Mathematics
1 answer:
ddd [48]3 years ago
3 0
Distribute ^4 to both 2 and q^5

2^4 = 2 x 2 x 2 x 2 = 16
(q^5)^4 = q^20

16(q^20) = 16q^20 

16q^20 is your answer

hope this helps
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Elena has $0.90. Kia has 10 times as much money
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Answer:

Kia has ten times more money than Elena. Kia has more money that Elena.

Troy has one-tenth of the money Elena has. Troy has less money than Elena.

Step-by-step explanation:

3 0
3 years ago
What is x^4+25 factored
OLga [1]

(x^2+5)(x^2-5)

I hope this helps :)

3 0
3 years ago
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I NEED HELP PLEASE, THANKS! :)
marissa [1.9K]

Answer:

x = 28.01t,

y = 10.26t - 4.9t^2 + 2

Step-by-step explanation:

If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -

x = ( 30 cos 20° )( time ),

y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2

To determine " ( 30 cos 20° )( time ) " you would do the following calculations -

( x = 30 * 0.93... = ( About ) 28.01t

This represents our horizontal distance, respectively the vertical distance should be the following -

y = 30 * 0.34 - 4.9t^2,

( y = ( About ) 10.26t - 4.9t^2 + 2

In other words, our solution should be,

x = 28.01t,

y = 10.26t - 4.9t^2 + 2

<u><em>These are are parametric equations</em></u>

5 0
3 years ago
Rewrite the quadratic function below in standard form y=3(x+2)(x-3)
babunello [35]
X=3(x^2-x_6)
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8 0
3 years ago
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A safety officer wants to prove that μ = the average speed of cars driven by a school is less than 25 mph. Suppose that a random
Akimi4 [234]

Answer:

t=\frac{24-25}{\frac{2.2}{\sqrt{14}}}=-1.70    

The degrees of freedom are given by:

df=n-1=14-1=13  

The p value for this case would be given by:

p_v =P(t_{(13)}  

Step-by-step explanation:

Information given

\bar X=24 represent the mean height for the sample  

s=2.2 represent the sample standard deviation

n=14 sample size  

\mu_o =25 represent the value that we want to test

t would represent the statistic

p_v represent the p value for the test

Hypothesis to verify

We want to cehck if the true mean is lees than 25 mph, the system of hypothesis would be:  

Null hypothesis:\mu \geq 25  

Alternative hypothesis:\mu < 25  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{24-25}{\frac{2.2}{\sqrt{14}}}=-1.70    

The degrees of freedom are given by:

df=n-1=14-1=13  

The p value for this case would be given by:

p_v =P(t_{(13)}  

8 0
3 years ago
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