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4 years ago

The electron configuration of Chromium is?

Chemistry

1 answer:

Zinaida [17]4 years ago

7 0

Answer:

[Ar] 3d⁵ 4s¹ ..................

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Antacids, such as Alka-Seltzer, use the reaction of sodium bicarbonate with citric acid in water solution to produce a fizz as f

Alex17521 [72]

Answer:

2.8248 g

Explanation:

First, consider the balanced chemical equation:

$3NaHCO_{3} +C_{6}H_{8}O_{7} --->3CO_{2} +3H_{2}O +Na_{3}C_{6}H_{5}O_{7}\\$

Then we calculate the number of moles in 4.11 g of citric acid:

n(citric acid)= $\frac{4.11g}{192g/mol}=0.0214mol$

According to the balanced reaction, one mole of citric acid produces 3 moles of carbon dioxide. That's 3 times the number f moles of citric acid. So we will do the same with the available number of moles of citric acid.

so n(carbon dioxide) = 0.0214 mol*3=0.0642 mol

mass(carbon dioxide)= mass*molar mass=0.0642 mol* 44g/mol

= 2.8248 g

8 0

3 years ago

Initially, [NH3(g)] = [O2(g)] = 3.60 M; at equilibrium [N2O4(g)] = 0.60 M. Calculate the equilibrium concentration for NH3.

natima [27]

The question is incomplete, here is the complete question:

Consider the reaction $4NH_3(g)+7O_2(g)\rightarrow 2N_2O_4(g)+6H_2O(g)$

Initially, $[NH_3(g)]=[O_2(g)]$ = 3.60 M; at equilibrium $[N_2O_4(g)]=0.60M$ . Calculate the equilibrium concentration for $NH_3$

Answer: The equilibrium concentration of ammonia is 2.8 M

Explanation:

We are given:

Initial concentration of $[NH_3(g)]$ = 3.60 M

Initial concentration of $[O_2(g)]$ = 3.60 M

For the given chemical equation:

$4NH_3(g)+7O_2(g)\rightarrow 2N_2O_4(g)+6H_2O(g)$

Initial: 3.60 3.60

At eqllm: 3.60-4x 3.60-7x 2x 6x

We are given:

Equilibrium concentration of $[N_2O_4(g)]$ = 0.60 M

Evaluating the value of 'x'

$\Rightarrow 2x=0.60\\\\\Rightarrow x=\frac{0.60}{2}=0.2$

So, equilibrium concentration of $NH_3=(3.60-4x)=(3.60-(4\times 0.2))=2.8M$

Hence, the equilibrium concentration of ammonia is 2.8 M

6 0

3 years ago

Name:

EleoNora [17]

Answer:

Explanation:

coffe

6 0

3 years ago

4. Again, have someone hold the mirror for you, slowly move at least 3 m away

faltersainse [42]

Closer is bigger................

8 0

3 years ago

The molar volume of gas at STP, in liters, is?

defon

The molar volume of a gas at STP, in liters, is 22.4

you then multiply 22.4 by 2 to get the answer to the next question:

You can use the molar volume to convert 2 mol of any gas to 44.8 L

You can also use the molar volume to convert 11.2 L of any gas to 0.500 mol.

Avogadro’s law tells you that 1.2 L of O2(g) and 1.2 L of NO2(g) are the same numbers of moles of gas.

7 0

3 years ago