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Leto [7]
3 years ago
12

In the Sandwiches mode, select the "Cheese" option and observe the equation given for the preparation of a cheese sandwich. When

the number of bread slices and cheese slices is set to "0," you will see that there is "no reaction." Now, in the equation, set the number of bread slices to "2" and the number of cheese slices to "1." You will see that the product formed by these three elements is one cheese sandwich with two slices of bread and one slice of cheese. Classify the following combination of bread and cheese according to the limiting ingredient in the preparation of the cheese sandwich mentioned above. Drag the appropriate items to their respective bins.
Chemistry
1 answer:
Nesterboy [21]3 years ago
5 0

1- 4 bread slices and 5 cheese slices

2- 6 bread slices and 2 cheese slices

3- 6 bread slices and 4 cheese slices

4- 8 bread slices and 3 cheese slices

5- 2 bread slices and 1 cheese slice

6- 4 bread slices and 1 cheese slice

7- 6 bread slices and 3 cheese slices

8- 8 bread slices and 5 cheese slices

Answer:

1)Bread is the limiting ingredients:

•4 bread slices and 5 cheese slices

•6 bread slices and 4 cheese slices

•8 bread slices and 5 cheese slices

2)Cheese is the limiting ingredients:

•6 bread slices and 2 cheese slices

•8 bread slices and 3 cheese slices

•4 bread slices and 1 cheese slice

3)There are no limiting ingredient

•6 bread slices and 3 cheese slices

•2 bread slices and 1 cheese slice

Explanation:

In a certain chemical reaction,if one of the reactant is present in small amount,the reaction stops abruptly once all of that reactant is used up.This reactant is called a limiting reagent. While the other ractant is called the excess reagent. Similarly, in the above mentioned question,the ingredient that was limiting was less in number while the other ingredient was in excess.

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Write the balanced equation. Then calculate the volume of 0.65 M HCl required to completely neutralize 400.0 ml of 0.88 M KOH.
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Hello!

The balanced equation for the neutralization of KOH is the following:

HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)

To calculate the volume of HCl required, we can apply the following equation:

 moles HCl = moles KOH \\  \\ cHCl*vHCl=cKOH*vKOH \\  \\ vHCl= \frac{cKOH*vKOH}{cHCl}= \frac{400 mL*0,88M}{0,65M}=  541,54mL

So, the required volume of HCl is 541,54 mL

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