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lakkis [162]
4 years ago
13

Question 1 of 10

Chemistry
1 answer:
zavuch27 [327]4 years ago
6 0
<h2>Answer:D</h2>

Explanation:

Let l be the wave length of the given wave.

Let v be the speed of the given wave.

Let f be the frequency of the given wave.

As we know,

l=\dfrac{v}{f}

Given,

v=3\times 10^{8}ms^{-1}\\f=9.98\times 10^{7}Hz

So,l=\frac{3\times 10^{8}}{9.98\times 10^{7}}=3m

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Please help me with this three questions
zheka24 [161]

Answer:

1. A. Thyroid Gland Function

B. detecting Blood Clots

C. Treating Cancer

2. An example would be how many are used as tracers for diagnostic purposes

3. Beneficial because it gives us ways to eleminate pests, by the sterile insect technique

Number three is kinda iffy a bit difficult to explain it may be explained better in your book.

7 0
3 years ago
As a part of a clinical study, a pharmacist is asked to prepare a modification of a standard 22g package of a 2% mupirocin ointm
Vesna [10]

Answer:

226.8 mg of mupirocin powder are required

Explanation:

Given that;

weight of standard pack = 22 g

mupirocin by weight = 2%

so weight of mupirocin = 2% × 22 = 2/100 × 22 = 0.44 g

so by adding the needed quantity of mupirocin powder to prepare a 3% w/w mupirocin ointment

mg of mupirocin powder are required = ?, lets rep this with x

Total weight of ointment = 22 + x g

Amount of mupirocin  = 0.44 + x g

percentage of mupirocin  in ointment is 3?

so

3/100 = 0.44 + x g / 22 + x g

3( 22 + x g ) = 100( 0.44 + x g )

66 + 3x g = 44 + 100x g

66 - 44 = 100x g - 3x g

97 x g = 22

x g = 22 / 97

x g = 0.2268 g

we know that; 1 gram = 1000 Milligram

so 0.2268 g = x mg

x mg = 0.2268 × 1000

x mg  = 226.8 mg

Therefore, 226.8 mg of mupirocin powder are required

8 0
3 years ago
Help! This is due tomorrow and my teacher didn't explain this topic very well so I'm totally lost!
nydimaria [60]

Answer:

sorry I'm a dumb small brain

Explanation:

my genes

6 0
3 years ago
How many total atoms are there in one molecule of C145H293O168?
nasty-shy [4]

Answer:

606 atoms

Explanation:

Add the numbers    145 + 293 + 168

4 0
3 years ago
Which process occurs at the anode in an electrochemical cell?
Fiesta28 [93]

The process that occurs at the anode in an electrochemical cell is the loss of electrons. The answer is number 2. Oxidation occurs as electrons are lost at the anode at one of the electrodes in both an electrolytic cell and a voltaic cell.

5 0
3 years ago
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